Question

Mass of a man is 80kg. Assuming that a human body Contains 70% water, calculate the total no. of water molecules present in the body of the man.​

Answer 1

Answer:

Given,

Maas of the man = 80 kg

Percentage of water molecules it contains = 70%

Therefore,

Total no. of water molecules mass present in our human body

$= 70 \: percent\: of \: 80kg$

$= \frac{70}{100} \times 80$

$= \frac{70}{5} \times \frac{4}{1}$

$= 14 \times 4$

$= 56$

Answer - The total number of water molecules present in our body is 56 kg.

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