Answer:
Kc = 47
Explanation:
From the given equation ,
H₂(g) + Cl₂(g) ⇌ 2 HCl(g)
The equilibrium constant for the above reaction , can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation .
Hence ,
Kc = [HCl(g) ]² / [ Cl₂(g) ]
[ H₂(g) ]
From the question ,
[HCl(g) ] = 1.6 M
[ Cl₂(g) ] = 0.39 M
[ H₂(g) ] = 0.14 M
Now, putting it in the above equation ,
Kc = [HCl(g) ]² / [ Cl₂(g) ]
[ H₂(g) ]
Kc = [ 1.6 M ]² / [ 0.39 M ][ 0.14 M ]
Kc = 47
Answer:
136 g Al₂O₃
Explanation:
Assuming you do not need to find the limiting reactant, to find the mass of Al₂O₃, you need to (1) convert grams O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles Al₂O₃ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (64.0 g).
Molar Mass (O₂): 32 g/mol
Molar Mass (Al₂O₃): 102 g/mol
4 Al + 3 O₂ -----> 2 Al₂O₃
64.0 g O₂ 1 mole 2 moles Al₂O₃ 102 g
----------------- x -------------- x ------------------------ x ------------- = 136 g Al₂O₃
32 g 3 moles O₂ 1 mole
50 divided by 100= 0.5 x100 = 50
So I think it’s 50 minutes sorry if it’s wrong.