9514 1404 393
Answer:
2) 3 pages per hour
3) 4/29 km per minute
Step-by-step explanation:
Division by a fraction is the same as multiplication by the inverse of that fraction.
<h3>2) </h3>

__
<h3>3) </h3>

<h3>AG = 27 and VA = 24. What is TO? </h3>
A. 45
B. 43
<h3>C. 36</h3>
D. 90
#CarryOnLearning.
What you can do in this case is the following rule of three to find the result:
1 light year ---> 5.88 * 10 ^ 12 miles
3.2 * 10 ^ 2 light year ---> x
Clearing x we have:
x = ((3.2 * 10 ^ 2) / (1)) * (5.88 * 10 ^ 12)
x = 1.88 * 10 ^ 15 miles
answer:
In scientific notation, approximately it is 1.88 * 10 ^ 15 miles
Answer:
We are given:

is the critical value at 0.02 significance level
is the margin of error
Therefore, the required sample size is:




Therefore, the required sample size n = 1061
Answer
a) k=7, h=9, the unique solution of the system is 
b) If k=6 and h=8 the system has infinite solutions.
c)If k=6 and h=9 the system has no solutions.
Step-by-step explanation:
I am assuming that the system is x1+3x2=4; 2x1+kx2=h
The augmented matrix of the system is
. If two times the row 1 is subtracted to row 2 we get the following matrix
.
Then
a) If k=7 and h=9, the unique solution of the system is
and solviong for
,

Then the solution is 
b) If k=6 and h=8 the system has infinite solutions because the echelon form of the matrix has a free variable.
c)If k=6 and h=9 the system has no solutions because the last equation of the system of the echelon form of the matrix is 