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Yanka [14]
3 years ago
10

Find the greatest value of -10+14X-2X^2 and state the value of X at which it occurs​

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

Step-by-step explanation:

a maximum or minimum occurs where the derivative equals zero

f(x) = -2x² + 14x - 10

f'(x) = -4x + 14

0 = -4x + 14

4x = 14

x = 3.5

f(3.5) = -2(3.5)² + 14(3.5) - 10 = 14.5

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8 0
3 years ago
ITO
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Using the speed - distance relationship, the time left before the appointed time is 27 minutes.

<u>Recall</u><u> </u><u>:</u>

  • Distance = speed × time

  • Let time = t

<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>

  • Distance = 10 × (t + 3) = 10t + 30 - - - (1)

<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>

  • Distance = 12 × (t - 2) = 12t - 24 - - - - (2)

<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>

10t + 30 = 12t - 24

<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>

10t - 12t = - 24 - 30

-2t = - 54

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>

t = 54 / 2

t = 27

Hence, the time left before the appointed time is 27 minutes.

Learn more : brainly.com/question/25669152

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Step-by-step explanation:

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