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SVETLANKA909090 [29]
1 year ago
5

One type of electromagnetic radiation has a frequency of 107.1MHz,another type has wavelength of of 2.12x10^-10 m,and another ty

pe of electromagnetic radiation has photons with energy equal to 3.97x10^19j/photon. Identify each type of electromagnetic radiation and place them in order of increasing photon energy and increasing frequency
Chemistry
1 answer:
Andreas93 [3]1 year ago
5 0

Each type of electromagnetic radiation and placed in order of increasing photon energy and increasing frequency

  • FM Radio waves < Visible light < X - rays
  • Order of increasing frequency.
  • FM Radio waves < Visible light < X - rays

This is further explained below.

<h3>What is electromagnetic radiation?</h3>

Parameters

Frequency =107 100 000 hertz

Wavelength, λ = c / ν => 2.8 m => 2.12 * 10-10 m

Energy = 3.97 * 10 -19 J/ photon.

Generally, the equation for Wavelength is  mathematically given as

λ = h c / E

Therefore

λ =6.626 * 10-34  * 3 * 108  / (3.97* 10 -19 J)

λ =5 * 10-7 m

In conclusion, This is considered to be part of the viewable area (green Increasing photon energy from lowest to highest.

  • FM Radio waves < Visible light < X - rays
  • Order of increasing frequency.
  • FM Radio waves < Visible light < X - rays

Read more about electromagnetic radiation

brainly.com/question/11895806

#SPJ1

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⦁ Find the concentration of H+, OH-, PH and POH of 0.03 M of magnesium hydroxide which ionizes to the extent of only 1 /3 in aqu
lions [1.4K]

Answer:

pH=12.3\\\\pOH=1.7\\

[H^+]=5x10^{-13}M

[OH^-]=0.02M

Explanation:

Hello there!

In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

Mg(OH)_2(s)\rightleftharpoons Mg^{2+}(aq)+2OH^-(aq)

Thus, since the ionization occurs at an extent of 1/3, we can set  up the following relationship:

\frac{1}{3} =\frac{x}{[Mg(OH)_2]}

Thus, x for this problem is:

x=\frac{[Mg(OH)_2]}{3}=\frac{0.03M}{3}\\\\x=  0.01M

Now, according to an ICE table, we have that:

[OH^-]=2x=2*0.01M=0.02M

Therefore, we can calculate the H^+, pH and pOH now:

[H^+]=\frac{1x10^{-14}}{0.02}=5x10^{-13}M

pH=-log(5x10^{-13})=12.3\\\\pOH=14-pH=14-12.3=1.7

Best regards!

4 0
3 years ago
The neutron is located in the what part of the atom
torisob [31]

Answer:

in the middle

Explanation:

4 0
3 years ago
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How is an oxidation half-reaction written using the reduction potential chart? How is the oxidation potential voltage determined
insens350 [35]
Oxidation  half  reaction  is  written   as    follows when  using  using  reduction potential  chart
example  when  using  copper  it is  written  as  follows
CU2+   +2e-  --> c(s)  +0.34v
 oxidasation  is the  loos  of  electron  hence copper oxidation  potential  is  as  follows
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7 0
3 years ago
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According to the Arrhenius concept, which of the following substances is NOT a base in aqueous solutionsA. NH3B. LiOHC. NaOHD. H
olga_2 [115]

Answer:

NH₃ (Option A)

Explanation:

Arrhenius theory explained that the acids are the ones that have H⁺, either H in its formula. Following this, the bases are the ones that have OH⁻ , either OH and its formula.

It can be used only with compounds with H, or OH.

So the ammonia is not a base, as Arrhenius theory.

It is known that ammonia behaves as a weak base, but it does not have hydroxide ions that can yield to water

5 0
3 years ago
A graduated cylinder contains 20.8 mL of water. What is the new water level, in milliliters, after 35.2 g of silver metal is sub
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<u>Answer:</u> The new water level of the cylinder is 24.16 mL

<u>Explanation:</u>

To calculate the volume of water displaced by silver, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of silver = 10.49 g/mL

Mass of silver = 35.2 g

Putting values in above equation, we get:

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We are given:

Volume of graduated cylinder = 20.8 mL

New water level of the cylinder = Volume of graduated cylinder + Volume of water displaced by silver

New water level of the cylinder = (20.8 + 3.36) mL = 24.16 mL

Hence, the new water level of the cylinder is 24.16 mL

5 0
3 years ago
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