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3 years ago

True or false water molecules are polymers

2 answers:

6 0

Yes, Polymers are materials made of long, repeating chains of molecules. ... Proteins are natural polymers made up of amino acids, and nucleic acids (DNA and RNA) are polymers of nucleotides — complex molecules composed of nitrogen-containing bases, sugars and phosphoric acid, for example.

MrMuchimi3 years ago

6 0

Well I’m pretty sure that they are because I’m learning it rn

You might be interested in

How many electrons elements are present in period 2 ?

AVprozaik [17]

There are Eight elements

3 0

2 years ago

Read 2 more answers

Which of the following elements is represented by the above graphic

kolezko [41]

Answer:

Sulfur

Explanation:

Sulfur has 16 valence electrons, as shown in the diagram.

5 0

2 years ago

The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i

german

The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.

5 0

3 years ago

Could someone please tell show me steps to solve this, I am so confused.

jonny [76]

And this is y I should of paid attention in that one science class in middle school that taught this...

(￣▽￣;)

6 0

3 years ago

A 6.165 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 10.27 grams of CO2 and 3

e-lub [12.9K]

Answer:

Explanation:

mass of carbon in 10.27 g of CO₂ = 12 x 10.27 / 44 = 2.80 g

mass of hydrogen ( H ) in 3.363 g of H₂O = 2 x 3.363 / 18

= .373 g

These masses would have come from the sample of 6.165 g .

Rest of 6.165 g of sample is oxygen .

So oxygen in the sample = 6.165 - ( 2.8 + .373 ) = 2.992 g

Ratio of C , H , O in the sample

2.8 : .373 : 2.992

C: H : O : : 2.8 : .373 : 2.992

Ratio of moles

C: H : O : : 2.8/12 : .373/1 : 2.992 / 16

C: H : O : : .2333 : .373 : .187

C: H : O : : .2333/.187 : .373/.187 : .187/.187

C: H : O : : 1.247 : 1.99 : 1

C: H : O : : 5 : 8 : 4 ( after multiplying by 4 )

Hence empirical formula

C₅H₈O₄

Molecular formula ( C₅H₈O₄ )n

n ( 5 x 12 + 8 x 1 + 4 x 16 ) = 132

n x ( 60 + 8 + 64 ) = 132

n = 1

Molecular formula = C₅H₈O₄.

3 0

2 years ago