Answer:
The Solar System moves through the galaxy with about a 60° angle between the galactic plane and the planetary orbital plane. The Sun appears to move up-and-down and in-and-out with respect to the rest of the galaxy as it revolves around the Milky Way
Explanation:
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Answer:
0.0745 mole of hydrogen gas
Explanation:
Given parameters:
Number of H₂SO₄ = 0.0745 moles
Number of moles of Li = 1.5107 moles
Unknown:
Number of moles of H₂ produced = ?
Solution:
To solve this problem, we have to work from the known specie to the unknown one.
The known specie in this expression is the sulfuric acid, H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.
Balanced chemical equation:
2Li + H₂SO₄ → Li₂SO₄ + H₂
From the balanced equation;
Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.
2 mole of Li reacted with 1 mole of H₂SO₄
1.5107 mole of lithium will react with
= 0.7554mole of H₂SO₄
But we were given 0.0745 moles,
This suggests that the limiting reagent is the sulfuric acid because it is in short supply;
since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;
0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas
Answer:One mole of HBr has 6.02 x 1
0
23
molecules of HBr.
1 mole of HBr = 6.02 x 1
0
23
molecules of HBr.-----(a)
X mole of HBr has 1.21 x
10
24
molecules of HBr.
X mole of HBr = 1.21 x
10
24
molecules of HBr------(b)
Taking ratio of (a) and (b)
X / 1 = 1.21 x
10
24
/ 6.02 x 1
0
23
X= 2.009 moles.
Explanation:
The sun heats up the air at different rates. Weather is caused by uneven heating
Answer: 0.17M
Explanation:
The equation for the reaction is :
2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O
From the balanced equation, we obtain :
nA = mole of acid = 2
nB = mole of the base = 1
From the question, we obtain:
Va = Vol. Of acid = 0.105L
Ma = conc. Of acid =?
Vb = Vol of base = 35.7 mL = 0.0357L
Mb = conc. of base = 0.25M.
We solve for the conc. of the acid using:
MaVa / Mb Vb = nA / nB
(Ma x 0.105) / (0.25x0.0357) = 2
Cross multiply to express in linear form. We have:
Ma x 0.105 = 0.25 x 0.0357 x 2
Divide both side by 0.105. We have
Ma = (0.25 x 0.0357 x 2) / 0.105
Ma = 0.17M
Therefore the concentration of the acid(HNO3) is 0.17M