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Elodia [21]
3 years ago
12

A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of o m

/s. By the time it reached the buoy, it was going 10 m/s. What was the average velocity of the boat?
A) -3.33 m/s^2
B) -1.11 m/s
C) +1.11 m/s
D) +3.33 m/s
Physics
2 answers:
kifflom [539]3 years ago
8 0

its +1.11 I TOOK THE TEST

MArishka [77]3 years ago
5 0
If you or any else needs the answer for this it is C. +1.11 m/s.
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Pa help po science po yan pang grade 7
AveGali [126]

Answer:

table 1:

1. 100/15 = 6.7 m/s

2. 100/12 = 8.3 m/s

3. 100/9 = 11.1 m/s

table 2:

1. 100/8 = 12.5 m/s

2. 100/6 = 16.7 m/s

3. 100/4 = 25 m/s

Explanation:

8 0
2 years ago
A small airplane takes on 302 l of fuel. If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?
ella [17]

To calculate the mass of the fuel, we use the formula

m = V \times  \rho

Here, m is the mass of fuel, V is the volume of the fuel and its value is V =302 \ L =  302 \ L \times \frac{10^{3}m L }{L} = 302 \times 10^{3} \ mL and  \rho is the density and its value of  0.821 g/mL.

Substituting these values in above relation, we get  

m = 302 \times 10^{3} \ mL \times 0.821 g/mL = 247942 g \\\\ m = 247. 94 \ kg

Thus, the mass of the fuel 247 .94 kg.

8 0
3 years ago
PLEASE HELP WILL GIVE 20 POINTS!!!!
Aliun [14]
A). very large
B). very small
These are both wishy-washy words ... words that mean different things
to different people, and may even mean different things to the same person
at different times.
Even if everybody agreed on the meaning of these words, we wouldn't
have any idea which one may apply to the rover, because there's nothing
in the picture that gives any size reference !  We don't know from the picture
whether this thing is the size of a school book or a school bus.  Or somewhere
in between.

C). very mathematical
What in the world does this mean ? ?
I don't see a single number or math symbol anywhere in the drawing.
I don't think this is the correct choice.

D). very complex
In the drawing, there are thirteen different labels of things,
and eight of them have such long names that only their initials
are shown.
This is one complicated combination of many different machines.
I think this is the best choice of description.
6 0
3 years ago
Read 2 more answers
Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M
stealth61 [152]

The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

- For M1, the only two forces acting on it are the force of gravity M_1 g (downward) and the tension in the string T (upward). So we can write

M_1 g - T = M_1 a

where

M_1 is the mass of the block

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, M_2 g sin \theta. So the equation of motion is

T-M_2 g sin \theta = M_2 a

where

M_2 = 13.5 kg is the mass of the 2nd block

\theta=35.5^{\circ} is the angle of the ramp

In order for the two blocks to be in equilibrium, the acceleration must be zero:

a=0

So the two equations become:

M_1 g - T=0\\T-M_2 g sin \theta = 0

Isolating T from the 1st equation,

T=M_1 g

And substituting into the 2nd equation, we can find the value of the mass M_1:

M_1 g - M_2 g sin \theta = 0\\M_1 = M_2 sin \theta = (13.5)(sin 35.5^{\circ})=7.8 kg

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
The position vector of a particle of mass 1.70 kg as a function of time is given by r with arrow = (6.00 î + 5.70 t ĵ), where r
ollegr [7]

Answer:

The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .

Explanation:

Given that,

Mass = 1.70 kg

Position vector r=(6.00\hat{i}+5.70 t \hat{j})

We need to calculate the angular velocity

The velocity is the rate of change of the position of the particle.

v = \dfrac{dr}{dt}

v=\dfrac{d}{dt}(6.00\hat{i}+5.70 t \hat{j})

v=5.70\hat{j}

We need to calculate the angular momentum of the particle

Using formula of angular momentum

L=r\cdot p

Where, p = mv

Put the value of p into the formula

L=m(r\times v)

Substitute the value into the formula

L=1.70(6.00\hat{i}+5.70 t \hat{j}\times5.70\hat{j})

L=1.70\times34.2

L=58.14\ kgm^2/s

Hence, The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .

7 0
2 years ago
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