Answer:
0.26g of NaCl is the maximum mass that could be produced
Explanation:
Based on the reaction:
HCl + NaOH → NaCl + H₂O
<em>Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl</em>
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To solve this question we need to find <em>limiting reactant. </em>The moles of limiting reactant = Moles of NaCl produced:
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl
<em>Moles NaOH -Molar mass: 40g/mol-:</em>
0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH
As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.
The mass of NaCl is:
<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>
0.0045 moles * (58.44g/mol) =
<h3>0.26g of NaCl is the maximum mass that could be produced</h3>
Answer:
Option B is correct.
A buffer is best used in pH ranges from one unit below up to one unit above its pKa.
Explanation:
The ability of a buffer solution to maintain a nearly constant pH when small amounts of acids or bases are added to the solution is greatest at the pKa & reduces as the pH of the solution goes above or below the pKa. A rule-of-thumb is to use a buffer within 1 pH unit of the pKa to maximize its buffering capacity.
Hope this Helps!
Answer:
It emits energy since to move from a higher energy level to a lower energy level or ground state, it must lose energy.
Answer:
pKa = 4.89.
Explanation:
We can solve this problem by using the <em>Henderson-Hasselbach equation</em>, which states:
pH = pKa + log
In this case [A⁻] is the concentration of sodium benzoate and [HA] is the concentration of benzoic acid.
We <u>input the given data</u>:
4.63 = pKa + log
And <u>solve for pKa</u>:
pKa = 4.89
Answer is C. the top LEFT side Is the smallest w/ most energy. The bottom RIGHT is the biggest in size but with lower energy levels.