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3 years ago

An atom of any element must contain

2 answers:

5 0

An atom (which by definition is neutral) should have (2) an equal number of protons and electrons.
If the number of protons and electrons are not equal, it becomes an ion.The number of protons and neutrons can vary widely depending on what the substance is and depending on the isotopes.

svetlana [45]3 years ago

4 0

An atom of any element must contain "<span>(2) an equal number of protons and electrons" but it should be noted that atoms can borrow electrons from one another. </span>

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liberstina [14]

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3 0

2 years ago

The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?

sweet [91]

Answer : The maximum amount of nickel(II) cyanide is $5.84\times 10^{-12}M$

Explanation :

The solubility equilibrium reaction will be:

$Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-$

Initial conc. 0.220 0

At eqm. (0.220+s) 2s

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ni^{2+}][CN^-]^2$

Now put all the given values in this expression, we get:

$3.0\times 10^{-23}=(0.220+s)\times (2s)^2$

$s=5.84\times 10^{-12}M$

Therefore, the maximum amount of nickel(II) cyanide is $5.84\times 10^{-12}M$

7 0

3 years ago

Lake Eola is a sinkhole lake. What reasoning best describes how it formed?

lutik1710 [3]

Answer: A

Explanation: the first answer is more reasonable than the rest of them , hope this helped

6 0

3 years ago

Read 2 more answers

The surface temperature on Venus may approach 757 K. What is this temperature in degrees Celsius?

kotykmax [81]

Explanation:

1 ) Temperature of Venus in Kelvins = 757 Kelvins

$0^oC=273 Kelvins$

Temperature of Venus in degrees Celsius = $757-273 K=484 K$

2 ) Temperature on Mercury at night = $-269^oF$

$(T)^oC=((T)^oF-32)\times \frac{5}{9}$

$(T)^oC=((-269)^oF-32)\times \frac{5}{9}=167.22^oC$

Temperature on Mercury at night in degree Celsius = 167.22° C

7 0

3 years ago

Read 2 more answers

A gas occupies 135 cm3 at 143. K. At what Celsius temperature will its volume be 140 cm3? Assume that pressure remains constant.

Agata [3.3K]

Answer:

New temperature T2 = -124.7 °C

Explanation:

Given:

Old volume V1 = 135 cm³

New volume V2 = 140 cm³3

Old temperature T1 = 143 K

Find:

New temperature T2

Computation:

V1 / T1 = V2 / T2

135 / 143 = 140 / T2

New temperature T2 = 148.3 K

New temperature T2 = 148.3 - 273

New temperature T2 = -124.7 °C

3 0

3 years ago