PLS HELP (30 points) Can you answer this Q???

Mathematics

1 answer:

Liula [17]3 years ago

4 0

Answer:

8 I dont know

Step-by-step explanation:

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F(x) = -4x2 + 4x – 4<br> Find f(3)

ValentinkaMS [17]

F(3) occurs when x =3. So lets plug 3 into our equation.

$f(3) = -4(3)^2 + 4(3)-4\\f(3) = -4(9) + 12- 4\\f(3) = -36 + 12- 4\\f(3)= -28$

F(3) = -28

I hope this helps! :)

5 0

3 years ago

Which of the following represents this function written in intercept form

Brilliant_brown [7]

Answer:

v=2(x - 1)(x-6)=2(x²-6x-x+6)=12x²-12x-2x+12

v = 12x²-14x+12 standard form

Step-by-step explanation:

3 0

3 years ago

Can someone how to get the answer? Thanks! PLEASE HELPpppppppppppppppppppppppp

Over [174]

$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right) \ \textgreater \ \ln \left(6^x\right)=\ln \left(21\right)$

$\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \ \ln \left(6^x\right)=x\ln \left(6\right)$

$x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \ \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)}$

$Therefore \: x=\frac{\ln \left(21\right)}{\ln \left(6\right)}$

In your case ln means $\frac{log 21}{log 6}$