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Delicious77 [7]
3 years ago
14

50 POINTS - FAIRLY SIMPLE QUESTION............. How does calcium carbonate react with rain when the rain is in the air, while ca

lcium carbonate is on earth?
Chemistry
2 answers:
solniwko [45]3 years ago
8 0
The water will react with the calcium carbonate to create agricultural lime. This occurs because the water is not pure water and has calcium in it. The calcium ions from the rain water undergo a chemical reaction with the calcium carbonate's carbonate ions. 
mr Goodwill [35]3 years ago
4 0
Ut dissloves or sommat
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fredd [130]
No, They need something to hold on to, such as dirt
8 0
3 years ago
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Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 10.0 kJ or greater.
nikdorinn [45]

Answer:

The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ

Explanation:

From Arrhenius equation showing the temperature dependence of reaction rates.

K = Ae^{\frac{Ea}{RT} } where

k = rate constant

A = Frequency or pre-exponential factor

Ea   =       energy of activation

R = The universal gas constant

T = Kelvin absolute temperature

we have

f = e^{\frac{Ea}{RT} }

Where

f = fraction of collision with energy higher than the activation energy

Ea = activation energy = 10.0kJ = 10000J

R = universal gas constant = 8.31 J/mol.K

T = Absolute temperature in Kelvin = 400K

In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature  

Plugging in the values into the equation relating f to activation energy we get

f = e^{\frac{10000J}{(8.31J/((mol)(K)))(400K)} } or f = e^{3.01} = 20.22 moles of argon have an energy of 10.0 kJ or greater

5 0
3 years ago
A student dissolves of styrene in of a solvent with a density of . The student notices that the volume of the solvent does not c
raketka [301]

Answer:

0.576M and 0.655m

Explanation:

<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>

<em />

Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:

<em>Moles styrene:</em>

Molar mass C₈H₈:

8C = 12.01g/mol*8 = 96.08g/mol

8H = 1.005g/mol* 8 = 8.04g/mol

96.08g/mol + 8.04g/mol = 104.12g/mol

Moles of 15.0g of styrene are:

15.0g * (1mol / 104.12g) = 0.144 moles of styrene

<em>Liters solution:</em>

250mL * (1L / 1000mL) = 0.250L

<em>kg solvent:</em>

250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg

Molarity is:

0.144 moles / 0.250L =

<h3>0.576M</h3>

Molality is:

0.144 moles / 0.220kg =

<h3>0.655m</h3>
8 0
3 years ago
How many grams of C3H8 would be needed to produce 6.39 grams of CO2?
just olya [345]

Answer:

2.13g

Explanation:

Atomic mass of CO2 =  12 + 32 = 44g/Mol

Atomic mass of C3H8 = 36 + 8 = 44g/Mol

Reaction

C3H8 + 5O2 --> 3CO2 + 4H2O

3CO2 = 6.39g

Required C3H8 = (6.39/(44 x 3)) x 44 = 2.13g  

8 0
2 years ago
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tekilochka [14]

Answer:

The top one is b i need the 2nd 1

Explanation:

7 0
2 years ago
Read 2 more answers
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