Ask question

Ask question

All categories

Delicious77 [7]

3 years ago

14

50 POINTS - FAIRLY SIMPLE QUESTION............. How does calcium carbonate react with rain when the rain is in the air, while ca

lcium carbonate is on earth?

2 answers:

solniwko [45]3 years ago

8 0

The water will react with the calcium carbonate to create agricultural lime. This occurs because the water is not pure water and has calcium in it. The calcium ions from the rain water undergo a chemical reaction with the calcium carbonate's carbonate ions.

mr Goodwill [35]3 years ago

4 0

Ut dissloves or sommat

You might be interested in

What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

3 years ago

Need help answering

svp [43]

Answer:

Your answer would be E

Explanation:

4 0

2 years ago

Reactions cannot occur without a certain minimum amount of energy. What is this minimum amount of energy called? A.the activatio

madam [21]

A. the activation energy

7 0

3 years ago

Read 2 more answers

Question<br> What is the molarity of a 400 mL solution containing 0.60 moles of NaCl?

Mumz [18]

Answer:

0.24 M

Explanation:

Molarity = Moles solute / Liters solution

Step 1: Identify variables

400 mL = Liters solution

0.60 moles = Moles solute

Step 2: Identify conversions

1 L = 1000 mL

Step 3: Convert mL to L

400mL(1 L/1000mL) = 0.4 L

Step 4: Find molarity

M = (0.4 L)(0.60 mol) = 0.24 M

6 0

2 years ago

What will most likely happen when stress is applied to an equilibrium reaction?

Irina-Kira [14]

Answer:

option D is the correct answer of this question.

8 0

1 year ago