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ruslelena [56]
3 years ago
11

Which of these is an example of an experiment?

Physics
1 answer:
Vsevolod [243]3 years ago
7 0
Add different quantities of water to three potted plants
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How much energy is stored in the capacitor when it is aa fully charged
lakkis [162]

Answer:

0.5*10uF * 16*16 =0.0128

Explanation:

I have no explanation just like my soul.

6 0
2 years ago
With speeds up to 90 miles per hour, what is the fastest sport on ice?.
Eddi Din [679]

Answer:

Luge

Explanation:

8 0
3 years ago
Similarities and differences between<br> distance Time graph and velocity time<br> graph?
egoroff_w [7]

Answer:

Similarity: >>Time is independent variable and such is on the x-axis. ... >>Distance time graph tells you how much distance you have travelled, while velocity time graph tells you your acceleration.  The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

4 0
3 years ago
A person hits a 45-g golf ball. The ball comes down on a tree root and bounces
Verizon [17]

Answer:

Maximum height, h = 10 m          

Explanation:

It is given that,

Mass of golf ball, m = 45 g = 0.045 kg

The ball comes down on a tree root and bounces  straight up with an initial speed of 14.0 m/s.

We need to find the height the ball will rise  after the bounce. It is based on the conservation of energy such that,

\dfrac{1}{2}mv^2=mgh

h is maximum height raised by the ball

h=\dfrac{v^2}{2g}\\\\h=\dfrac{(14)^2}{2\times 9.8}\\\\h=10\ m

So, the ball will raised to a height of 10 meters.

5 0
3 years ago
A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find
butalik [34]

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

weight of the rock m = 3.00N  

solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy    ..............................1

so it can be written as

work = force × distance     ...................2

and

KE is express as

K.E = 0.5 × m × v²  

and it can be written as

F × d = 0.5 × m × (vf)² - (vi)²      ......................3

here

m is mass and vi and vf is initial and final velocity

F = mg = m  (-9.8)  , d = 15 m and v{f} = 25 m/s

so put value in equation 3 we get

m  (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

solve it we get

(vi)² =  919

vi = 30.32 m/s

so initial speed of the rock is 30.32 m/s

5 0
3 years ago
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