Studying more difficult subjects first is an effective study habit because

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery

Gelneren [198K]

Answer:

B. 0.51 ohms

Explanation:

Our data is as follows:

Resistor R = 20.0ohms

V1 = 12 volts

V2 = 0.300 V

We are to get the internal resistance of this battery

Now,

I = change in voltage/R

Change in voltage = v1-v2

= 12-0.300

= 11.7

Then,

I = 11.7/20

= 0.585Ri

Now

O.300 = 0.585Ri

Ri = 0.300/0.585

= 0.51 ohms

This is therefore the internal resistance of the battery.

Thank you!

6 0

3 years ago

In Part l, the independent variable was

Ber [7]

Answer:

The independent variable is the variable the experimenter manipulates or changes, and is assumed to have a direct effect on the dependent variable. ... The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

7 0

3 years ago

A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0

4 years ago

Describing motion verbally with distance and displacement

Dima020 [189]

Answer: Distance is the actual position traveled by an object. Displacement is the shortest distance covered by the object.

Explanation:

Distance is the actual length covered by an object from one position to another. It is a scalar quantity. It cannot be negative.

Displacement is the shortest distance covered by the object. The displacement can be calculated by subtracting initial distance from the final distance. It is vector quantity. The displacement covered by an object can be zero, negative and positive.

Suppose, the boy travels from home to school then come back to his home. The distance between from his home to his school is 3 km.

In this case, the boy covers the total distance from home to school then to home is 6 km. But the displacement is zero because he comes to same position.

7 0

3 years ago

You are driving up an inclined road. After 3.0 km you notice a roadside sign that indicates that your elevation has increased by

shutvik [7]

Answer:

~3°

Explanation:

x^2 + 0.16^2 = 3^2

x^2 + 0.0256 = 9

x^2 = 8.9744

x = sqrt(8.9744) = 2.99... = ~3

8 0

3 years ago