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4 years ago

What is meant by a charge carrier hole in a semiconductor? Can it be created in a conductor?

Physics

1 answer:

lara [203]4 years ago

6 0

Answer:

The materials used to make electronic components like transistor and integrated, circuit behave as if effective particles known as electron through them, causing electrical properties

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A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

When one side of the Earth is at high tide, then the opposite side of the Earth is also at high tide.

Rudiy27

<span>It is true because the near side of the moon is attracted by the gravitational force due to the alignment of the planet in one Straight line.The opposite side is due to the movement of earth towards moon side during alignment.Soon both side, there will be high tide at the same time.</span>

8 0

4 years ago

A man lowers an object of mass 12 kg from a height of 0.5m to the floor. What is the work done by him?

Olenka [21]

Answer:

Work = Force × distance

= m × g × d

= 12 × 9.8 × 0.5

= 58.8 N

If in the case , you need any help pleasee leg me know! [ you'll have to pay btw]

3 0

2 years ago