Divide the flow rate (0.750 m³/s) by the cross-sectional area of each pipe:
diameter = 40 mm ==> area = <em>π</em> (0.04 m)² ≈ 0.00503 m²
diameter = 120 mm ==> area = <em>π</em> (0.12 m)² ≈ 0.0452 m²
Then the speed at the end of the 40 mm pipe is
(0.750 m³/s) / (0.00503 m²) ≈ 149.208 m/s ≈ 149 m/s
(0.750 m³/s) / (0.0452 m²) ≈ 16.579 m/s ≈ 16.6 m/s
Answer:
c. Moon A is four times as massive as moon B
Explanation:
Let's assume the:
- mass of the object =

- mass of the moon A =

- mass of the moon B =

- distance between the center of masses of the object and moon B =

According to the given condition the object is twice as far from moon A as it is from moon B
- ∴distance between the center of masses of the object and moon B =

<u>As we know, gravitational force of attraction is given by:</u>

<em>According to the condition</em>
Force on m due to
Force on m due to



Answer:
4.93 m
Explanation:
According to the question, the computation of the height is shown below:
But before that first we need to find out the speed which is shown below:
As we know that


= 9.92 m/s
Now


98.4064 = 19.96 × height
So, the height is 4.93 m
We simply applied the above formulas so that the height i.e H could arrive
1. Ernerst Rutherford =====> Discovery of Atomic Nucleus
2. James Chadwick =====> Discovery of Neutron
3. Henri Becquerel =====> Discovery of Radioactivity
4. J.J. Thomson =====> Discovery of Electron
Answer:
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