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umka2103 [35]
3 years ago
14

Make a neutral Beryllium atom by adding protons, neutrons and electrons. Now, what would you do to make a

Chemistry
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

4 protons, 5 neutrons, 4 electrons to have the neutral Be atom

the only way to make a negative Be is to have more than 4 electrons

Explanation:

Make a neutral Beryllium atom by adding protons, neutrons and electrons. Now, what would you do to make a

beryllium atom with a negative charge?

Be has an atomic number of 4, an atomic mass 9

its atomic number tells us it has 4 protons, with a +4 charge

its atomic mass = neutrons + protons, so it has 5 neutrons with no charge

its neutral atom will have 4 electrons each with a negative charge to balance the +4 total proton harge.

so

4 protons, 5 neutrons, 4 electrons to have the neutral Be atom

to make a negative Be species, it still must have an atomic number of 4,

or it is not Beryllium

so the only way to make a negative Be is to have more than 4 electrons

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We can use the magnification equation for this problem.

Magnification equation:

<em>hi/h0 = di/d0</em>

Where in <em>hi </em>: image size, <em>h0</em> : object size, <em>di </em>: image distance, <em>d0 </em>: object distance from mirror

So plugging in the given variables we will have the corresponding equation

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3 years ago
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3 0
3 years ago
Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca
lina2011 [118]

<u>Answer:</u> The above reaction is non-spontaneous.

<u>Explanation:</u>

For the given chemical reaction:

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Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=-0.23-0.77=-1.0V

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

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3 0
3 years ago
1. The two qualities used to describe winds are________ and speed. 2. a local wing that blows during the day from an ocean towar
Mazyrski [523]
<span>1. The two qualities used to describe winds are direction and speed.
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sergejj [24]

Answer:

A. 35Cl1-

Explanation:

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7 0
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