1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka2103 [35]
3 years ago
14

Make a neutral Beryllium atom by adding protons, neutrons and electrons. Now, what would you do to make a

Chemistry
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

4 protons, 5 neutrons, 4 electrons to have the neutral Be atom

the only way to make a negative Be is to have more than 4 electrons

Explanation:

Make a neutral Beryllium atom by adding protons, neutrons and electrons. Now, what would you do to make a

beryllium atom with a negative charge?

Be has an atomic number of 4, an atomic mass 9

its atomic number tells us it has 4 protons, with a +4 charge

its atomic mass = neutrons + protons, so it has 5 neutrons with no charge

its neutral atom will have 4 electrons each with a negative charge to balance the +4 total proton harge.

so

4 protons, 5 neutrons, 4 electrons to have the neutral Be atom

to make a negative Be species, it still must have an atomic number of 4,

or it is not Beryllium

so the only way to make a negative Be is to have more than 4 electrons

You might be interested in
What is electron configuration of oxygen in its excited state​
timofeeve [1]

Answer:

1 {s}^{2} 2 {s}^{2} 2 {p}^{4}

OR

2 : 6

3 0
3 years ago
Read 2 more answers
5. A box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C. Which of the following statements
love history [14]

B. The partial pressure of N2 is 101 kPa

<h3>Further explanation</h3>

Given

volume = 22.4 L

1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C

Required

Total pressure and partial pressure

Solution

Ideal gas law :

PV = nRT

n total = 3 mol

T = O °C + 273 = 273 K

P = nRT/V

P = 3 x 0.08205 x 273 / 22.4

P total = 3 atm = 303,975 kPa

P Nitrogen = 1/3 x 303.975 = 101.325 kPa

P Hydrogen = 2/3 x 303.975 = 202.65 kPa

7 0
3 years ago
How many moles are in 5.03 x 1023 molecules?
AlladinOne [14]

Answer:

Some formulas for calculating mole are

Mole = Mass/ Molar mass

Mole = no of particles / avogadros constant

NB : no of particles can be no of atoms , no of ions , or no of molecules 2. Avogadros number or constant = 6.02 times 10 ^23

so we will be using the second formula

Mole = no of particles / avogadros constant

Mole =  5.03 x 10 ^23/6.02 x10^23

Mole = 8.355x10^45

hope it helps :)

Explanation:

4 0
3 years ago
What does stoichiometry use to relate moles of one molecule to moles of
Shkiper50 [21]
It is A I took it befor hope this helps:)
6 0
2 years ago
Which nitrogenous base is NOT found in DNA? *
scoundrel [369]

Answer:

c. uracil

Explanation:

uracil is not found in DNA. the missing base would be thymine

5 0
3 years ago
Other questions:
  • Which statement represent an abiotic environmental factor in an ecosystem?
    15·1 answer
  • The space shuttle heats up during reentry. Which term best describes what is causing
    5·1 answer
  • Using complete subshell notation (not abbreviations, 1s 22s 22p 6 , and so forth), predict the electron configuration of each of
    13·1 answer
  • A closed circle with short lines inside on a topographical map
    14·2 answers
  • A 6.40 g sample of solid KCl was dissolved in 42.0 g of water. The initial temperature of the water was 20.60°C. After the compo
    6·1 answer
  • A weather balloon has a volume of 1750 L at 103 kPa. The balloon is then released to the atmosphere. What is the pressure if at
    15·1 answer
  • If 35.0 grams of coal (carbon) burns in 58.5 grams of oxygen gas, how many grams of carbon dioxide can be produced? Describe the
    7·1 answer
  • How will you prepare hydrogen from zinc and dilute acid.​
    8·1 answer
  • The ability of nitrogen to attract electrons is
    14·1 answer
  • Answer, please!!!!!!
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!