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beks73 [17]
2 years ago
11

On diesel engines, data from ________ sensors are commonly used to adjust exhaust gas recirculation (EGR) rates.

Engineering
1 answer:
e-lub [12.9K]2 years ago
3 0

Answer:

Air mass sensors is the right answer i think

Explanation:

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An npn BJT has emitter, base, and collector doping levels of 1019 cm????3, 5 1018 cm????3, and 1017 cm????3, respectively. It is
Darina [25.2K]

Answer:

Explanation:

The answer to the given problem is been solved in the fine attached below.

8 0
3 years ago
Spring-loaded rack guide yokes are made of ______ and have a spring that pushes on the back side of the rack to help reduce the
Kobotan [32]

Answer:

metal

Explanation:

A yoke assembly are use in an assembly of a rack and pinion steering gear for a vehicle. The spring loaded yokes guided with a rack are made up of metals. It consists of a spring made of steel which pushes the back side of the rack to reduce the play that occurs between the pinion and the rack and still allow the relative motion.

6 0
3 years ago
A bearing is to be used as shaft support to carry both radial and thrust forces. Calculations show that a 02 series ball bearing
shepuryov [24]

Answer:

The correct answer is "20.8 kN" and "31 kN". A further explanation is given below.

Explanation:

  • The angular touch bearing seems to be a fine replacement while accommodating radial and even some displacement pressures.
  • You may receive static as well as dynamic scores from either the manufacturer's collections.  

The load ratings should be for the SKF bearing including its predetermined distance:

Static load

= 20.8 kN

Dynamic load

= 31 kN

4 0
3 years ago
Hello, I want to introduce you to our hosting - VPSDOM
Solnce55 [7]

Answer:

pogchamp

Explanation:

sussy balls

4 0
3 years ago
The maximum capacity of a 2-lane carriageway of a four lane dual carriageway is 2000 veh/hour. due to pipe laying operations the
Yuki888 [10]

Based on the maximum capacity as a result of the pipe-laying operations, and the maximum capacity without obstruction to the four-lane dual carriageway, the mean speed of traffic in the bottleneck is -2.73km.

<h3>What is the mean speed of traffic?</h3>

This can be found as:

= (Maximum restricted capacity - freeflowing rate) / (Kb - Ka)

= (1,100 - 1,500) / (209 - 62.5)

= -2.73 km/h

The rate that the queue outside the bottleneck grows is:

= Free flowing rate - (mean speed of traffic x ka)

= 1,500 - (-2.73 x 62.5)

= 1,670 veh/hour

Find out more on bottleneck at brainly.com/question/9551615

#SPJ1

3 0
1 year ago
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