To determine the quantity of pure CaCl2 from the given amount of CaCl2.9H2O, we use the ratio of CaCl2 to CaCl2.9H2O. From the formula the ratio would 1 is to 1 We calculate as follows:
7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( <span>110.98 g / 1 mol ) = 3.05 g CaCl2
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It is correct to state that Amines are suitable for preparing buffers are often synthesized by treating ammonia with epoxides. The relative structures of compound B are attached accordingly.
<h3>What is an Amine?</h3>
Amine is a family of basic chemical compounds formed by replacing hydrogen with one or more monovalent hydrocarbon radicals.
Apart from medications and pharmaceuticals, amines are employed in the production of azo-dyes and nylon.
They are commonly employed in the development of crop protection, pharmaceutical, and water purification chemicals. They are also used in personal care products.
Ethanol amines are the most widely utilized form of amine on the global market.
It should be noted that ammonia attacks epoxides at the least substituted carbon to produce (A.)
The generated product is then made to react with another epoxide, resulting in the synthesis of successive products.
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Epidermis is the answer to your question
Answer:
The number of moles of H₃PO₄ that reacted is 0.000343 moles
Note: Some data is missing. Data from the attachment is used for the calculationsinnthe explanation below.
Explanation:
The reaction is a neutralization reaction between NaOH and H₃PO₄. The equation of the reaction is given as follows:
3 NaOH + H₃PO₄ ---> Na₃PO₄ + 3 H₂O
The molarity of the NaOH solution is 0.238 mol/L.
Average volume of NaOH used during the titration to arrive to endpoint = (4.6 + 3.9 + 4.5) mL / 3 = 4.33 mL
Molarity is defined ratio of the number of moles of solute to the volume of solution. Mathematically, molarity = number of moles/volume in Litres
Number of moles of NaOH reacted = 0.238 mol/L × (4.33mL × 1 L/1000 mL)
Number of moles of NaOH = 0.00103 moles
From the equation of the reaction, 3 moles of NaOH reacts with 1 mole of H₃PO₄
0.00103 moles of NaOH will react with 0.00103 x 1/3 moles of H₃PO₄ = 0.000343 moles of H₃PO₄.
Therefore, number of moles of H₃PO₄ that reacted is 0.000343 moles
Answer:
Total of 4 isomers of hepta-2,4-diene are given
Explanation:
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