Answer: The moles of silver nitrate reacted is 5.72 moles, moles of iron (II) nitrate produced is 2.86 moles and moles of silver chloride produced is 5.72 moles

Explanation:

We are given:

Moles of iron (II) chloride = 2.86 moles

For the given chemical equation:

$FeCl_2(aq.)+2AgNO_3(aq.)\rightarrow Fe(NO_3)_2(aq.)+2AgCl(s)$

For silver nitrate:

By Stoichiometry of the reaction:

1 mole of iron (II) chloride reacts with 2 moles of silver nitrate.

So, 2.86 moles of iron (II) chloride will react with = $\frac{2}{1}\times 2.86=5.72mol$ of silver nitrate

Moles of silver nitrate reacted = 5.72 moles

For iron (II) nitrate:

By Stoichiometry of the reaction:

1 mole of iron (II) chloride produces 1 mole of iron (II) nitrate

So, 2.86 moles of iron (II) chloride will produce = $\frac{1}{1}\times 2.86=2.86mol$ of iron (II) nitrate

Moles of iron (II) nitrate produced = 2.86 moles

For silver chloride:

By Stoichiometry of the reaction:

1 mole of iron (II) chloride produces 2 moles of silver chloride

So, 2.86 moles of iron (II) chloride will produce = $\frac{2}{1}\times 2.86=5.72mol$ of silver chloride

Moles of silver chloride produced = 5.72 moles

Hence, the moles of silver nitrate reacted is 5.72 moles, moles of iron (II) nitrate produced is 2.86 moles and moles of silver chloride produced is 5.72 moles

7 0

3 years ago

If a solution is saturated, which of these is true?

svp [43]

A saturated solution is one where no more solid can dissolve at the temperature and pressure used

8 0

3 years ago

Read 2 more answers

In a particular reaction, 53.8 g of liquid silicon tetrachloride is added to 65.0 g of solid magnesium to produce solid magnesiu

kotykmax [81]

Answer: Mg is the excess reactant for the forward reaction.

Explanation: It is a stoichiometry problem and solved with the help of given grams and using balanced equation. Grams of both the reactants are converted to moles and divided by their coefficients. The excess reactant is the one for which we get the highest number on doing above steps.

The balanced equation is:

$SiCl_4(l)+2Mg(s)\rightarrow 2MgCl_2(s)+Si(s)$

Molar mass of silicon tetra chloride is 169.9 gram per mol and the molar mass of Mg is 24.3 gram per mol.

$53.8gSiCl_4(\frac{1mol}{169.9g})$

= $0.317molSiCl_4$

$65.0gMg(\frac{1mol}{24.3g})$

= 2.67 mol Mg

From balanced equation, the coefficient of silicon tetra chloride is 1 and that of Mg is 2. So, we will divide the moles of silicon tetra chloride by 1 and that of Mg by 2 and see which one gives highest number.

For silicon tetra chloride, $\frac{0.317}{1}$ = 0.317

and for Mg, $\frac{2.67}{2}$ = 1.34

The highest number is for Mg and so the excess reactant for the forward reaction is Mg.

7 0

3 years ago

Write a sentence that descrices how to determine the number of moles of a compound in known mass of a

sattari [20]

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

For example ,

For a compound X ,

The given mass i.e. w = 20 g

and the molecular mass ,i.e. , m = 10 g / mol

Then the moles can easily be calculated by using the above formula ,

n = w / m

n = 20 g / 10 g/mol = 2 mol

Hence , answer = 2 mol.

6 0

3 years ago