Answer : The specific heat of the metal is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of ice = 
= mass of metal = 1.00 kg
= mass of ice = 1.00 kg
= final temperature of mixture = 
= initial temperature of metal = 
= initial temperature of ice = 
Now put all the given values in the above formula, we get:
![(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]](https://tex.z-dn.net/?f=%281.00kg%29%5Ctimes%20c_1%5Ctimes%20%28-8.88-5.00%29%5EoC%3D-%5B%281.00kg%29%5Ctimes%202000J%2Fkg%5EoC%5Ctimes%20%28-8.88-%28-24.0%29%29%5EoC%5D)
Therefore, the specific heat of the metal is,
Prime factorization means that we divide 90 by prime numbers only.
90 ÷ 2 = 45
45 ÷ 3 = 15
15 ÷ 3 = 5
2 x 3 x 3 x 5 = 90
2 x 3² x 5 = 90
or 2,3,3,or 5
Answer: y ≈ 10.6 cm
Step-by-step explanation:
The cosine function relates the adjacent side to the hypotenuse in a right triangle. The side adjacent to the 20° angle is 10 cm.
cos(20°) = (10 cm)/y
y = (10 cm)/cos(20°)
y ≈ 10.6 cm
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