Solve the system of linear equations by elimination.

Mathematics

2 answers:

nadya68 [22]2 years ago

8 0

Hey! Hopefully this helped :)

Vinil7 [7]2 years ago

8 0

12, 6

First Simplify
3x - 30 = y
7y - 6 = 3x

Next, Eliminate One of the variables
6y = 36

Divide
y = 6

Substitute y and solve
-3x + 7 x 6 = 6
X = 12

Checker solution, not necessarily needed
3 x 12 - 30 = 6
7 x 6 - 6 = 3 x 12
6 = 6
36 = 36

12, 6 Is the Answer
or another way to put it is
(x, y) = (12, 6)

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Suppose that each quarter at a particular community college Jared has to pay $729 in tuition and $22 in fees.

k0ka [10]

Answer:

$\$3755$

Step-by-step explanation:

For 1 Quarter:

$Amount\ paid\ in\ tuition=\$729\\\\Amount\ paid\ in\ fees=\$22\\\\Total\ amount\ paid\ in\ 1\ Quarter=Amount\ paid\ in\ tuition+Amount\ paid\ in\ fees\\\\Total\ amount\ paid\ in\ 1\ Quarter=729+22\\\\Total\ amount\ paid\ in\ 1\ Quarter=\$ 751$

For 5 Quarter:

$Remaining\ Quarters=5\\\\Total\ amount\ paid\ in\ 5\ Quarter=Number\ of\ quarters\times Total\ amount\ paid\ in\ 1\ Quarter\\\\Total\ amount\ paid\ in\ 5\ Quarter=5\times 751\\\\Total\ amount\ paid\ in\ 5\ Quarter=\$3755\\\\So\ total\ \$3755\ is\ required\ for\ tuition\ and\ fees.$