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3 years ago

What type of circuit is illustrated?

Physics

2 answers:

Elis [28]3 years ago

8 0

A. Parallel circuit

Short circuits are circuits that is like plugging in a USB into your computer and the other end to your iPhone, so it's not D.

Series circuits can come in all kinds of different shapes, so it's not C.

Open circuits are circuits that are opened, meaning that whenever you turn on the light and it's an open circuit, it won't work cause the two wires are not connected, meaning it's not D.

Parallel circuits are circuits that are in one straight line, just like parallel lines, meaning the answer would be A. (Look at the picture and don't get confused with the other question that's the same question and has the same answers, they both have different pictures, so look at the pictures they give you whenever they ask the question so your getting the right answer)

Hope this helped.

Ber [7]3 years ago

4 0

It will either be <span>A.parallel circuit or C.series circuit it depends on the picture because there are 2 of the same questions with the same picture on the test. ( i know this because i use K12).
Hope This Helps!
~Cupkake </span>

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A 3.5-cm radius hemisphere contains a total charge of 6.6 × 10–7

spayn [35]

As per Gauss Law

Net flux through enclosed surface is

$\phi = \frac{Q}{\epsilon_0}$

here through this hemisphere total flux will pass through two portions

1). from the curved surface

2). from flat circular base

so now we have

$\phi_{base} + \phi_{surface} = \frac{Q}{\epsilon_0}$

given that

$Q = 6.6 * 10^{-7} C$

$\phi_{surface} = 9.8 * 10^4$

now we have

$\phi_{base} + 9.8*10^4 = \frac{6.6*10^7}{8.85 * 10^{-12}}$

$\phi_{base} = - 9.8 *10^4 + 7.46 * 10^4$

$\phi_{base} = - 2.34 * 10^4 N*m^2/C$

4 0

2 years ago

It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously

Svetlanka [38]

The sound intensity level of 100 physics professors talking simultaneously is equal to 72 decibel.

<u>Given the following data:</u>

Sound intensity = 52 dB.

<h3>What is sound intensity?</h3>

Sound intensity can be defined as a measure of the power of a sound wave per unit area. Thus, sound intensity is a quantity that can be used to measure the energy of sound and its unit of measurement is Watts per square meter.

<h3>How to calculate the sound intensity level.</h3>

Mathematically, sound intensity level is given by this formula:

$\beta = 10 log(\frac{I}{I_{ref}} )$

<u>Note:</u> The reference value of sound intensity is equal to $1.0 \times 10^{-12}\;W/m^2$

Thus, the sound intensity for one (1) professor is given by:

$I_1 = 1.0 \times 10^{-12} \times 10^{5.2}\\\\I_1=1.585 \times 10^{-7}\;W/m^2$

For 100 professors, the sound intensity is:

$I_{100} = 1.585 \times 10^{-7} \times 100\\\\I_{100}=1.585 \times 10^{-5}\;W/m^2$

Substituting the parameters into the formula, we have;

$\beta = 10 log(\frac{1.585 \times 10^{-5}}{1.0 \times 10^{-12}})\\\\\beta = 10 log(15.58 \times 10^{6})\\\\\beta = 10 \times 7.2\\\\\beta =72\;dB$

Read more on sound intensity here: brainly.com/question/17062836

<u>Complete Question:</u>

One physics professor talking produces a sound intensity level of 52 dB. It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?

7 0

1 year ago

How to solve these two questions?

hammer [34]

1) See attached figure

The relationship between charge and current is:

$i = \frac{Q}{t}$

where

i is the current

Q is the charge

t is the time

Therefore, the current is the rate of change of the charge passing through a given point over time.

This means that for a graph of charge over time, the current is just equal to the slope of the graph.

For the graph in this problem:

- Between t = 0 and t = 2 s, the slope is

$\frac{50-0}{2-0}=25 C/s$

therefore the current is

i = 25 A

- Between t = 2 s and t = 6 s, the slope is

$\frac{-50-(50)}{6-2}=-25 C/s$

therefore the current is

i = -25 A

- Between t = 6 s and t = 8 s, the slope is

$\frac{0-(-50)}{8-6}=25 C/s$

therefore the current is

i = 25 A

The figure attached show these values plotted on a graph.

2) $15 \mu C$

The previous equation can be rewritten as

$Q = i t$

This equation is valid if the current is constant: if the current is not constant, then the total charge is simply equal to the area under a current vs time graph.

Here we have the current vs time graph, so we gave to find the area under it.

The area of the first triangle is:

$A_1 = \frac{1}{2}(0.001 s)(0.010 A)=5\cdot 10^{-6} C$

While the area of the second square is

$A_2 = (0.002 s - 0.001 s)(0.010 A)=1\cdot 10^{-5}C$

So, the total area (and the total charge) is

$Q=A_1 +A_2 = 5\cdot 10^{-6} + 1\cdot 10^{-5} = 1.5\cdot 10^{-5}C=1.5 \mu C$

3 0

3 years ago

Object A weighs 750 N on earth. Object B weighs 750 N on Jupiter.

Katarina [22]

The object A has the greater mass compared to object B.

<u>Explanation: </u>

The weight of any object on any planet is the measurement of gravity’s influence acting on the mass of the object. So for Earth, the acceleration will be acting on the object A’s mass (m) in Earth leading to the weight of the object A as 750 N.

While the acceleration of Jupiter will be acting on the object B’s mass kept in Jupiter to attain the weight of 750 N. So, the mass of both the objects at their respective planet will vary depending on the acceleration of each planet. We can check this as below:

$\text { object A's weight }=\text { m of object A } \times \text { Acceleration of Earth}$