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son4ous [18]
4 years ago
13

What type of circuit is illustrated?

Physics
2 answers:
Elis [28]4 years ago
8 0
A. Parallel circuit

Short circuits are circuits that is like plugging in a USB into your computer and the other end to your iPhone, so it's not D.

Series circuits can come in all kinds of different shapes, so it's not C.

Open circuits are circuits that are opened, meaning that whenever you turn on the light and it's an open circuit, it won't work cause the two wires are not connected, meaning it's not D.

Parallel circuits are circuits that are in one straight line, just like parallel lines, meaning the answer would be A. (Look at the picture and don't get confused with the other question that's the same question and has the same answers, they both have different pictures, so look at the pictures they give you whenever they ask the question so your getting the right answer)

Hope this helped.


Ber [7]4 years ago
4 0
It will either be <span>A.parallel circuit or C.series circuit it depends on the picture because there are 2 of the same questions with the same picture on the test. ( i know this because i use K12).
Hope This Helps!
~Cupkake </span>
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The principal quantum number is given the symbol and has positive, whole-number values starting from?
deff fn [24]

Answer:

Principal quantum numbers are denoted by the symbol 'n'. They designate the principal electron shell of the atom. The positive whole number values starting from 1,2,3 and so on..

Explanation:

All orbitals that have the same value of n are said to be in the same shell (level). For a hydrogen atom with n=1, the electron is in its ground state; if the electron is in the n=2 orbital, it is in an excited state. The total number of orbitals for a given n value is n2.

6 0
2 years ago
vector J is 3250m long in a 38.4 direction. Vector K is 1822 m long in a 58.8 direction. Find the magnitude and direction of the
garik1379 [7]

Answer:

The resultant vector has a magnitude of 4998 m and a direction of 45.7°.

Explanation:

The x component of the resultant vector is the sum of the x components of each individual vector.

x = 3250 cos 38.4 + 1822 cos 58.8

x = 3490.8

Similarly, the y component of the resultant vector is the sum of the y components of each individual vector.

y = 3250 sin 38.4 + 1822 sin 58.8

y = 3577.2

The magnitude can be found with Pythagorean theorem:

√(x² + y²)

√(3490.8² + 3577.2²)

4998

The direction can be found with trigonometry:

atan(y / x)

atan(3577.2 / 3490.8)

45.7°

The resultant vector has a magnitude of 4998 m and a direction of 45.7°.

3 0
3 years ago
Light is incident from air on the surface of a glass slab, which has an index of refraction of 2.5 In the air the light beam mak
djverab [1.8K]

Answer:

13.26°

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 35.0° )

{\theta_r} is the angle of refraction  ( ? )

{n_r} is the refractive index of the refraction medium  (glass, n=2.5)

{n_i} is the refractive index of the incidence medium (air, n=1)

Hence,  

1\times {sin35.0^0}={2.5}\times{sin\theta_r}

Angle of refraction= sin⁻¹ 0.2294 = 13.26°.

<u>13.26° is the angle of the beam with the normal in the glass.</u>

3 0
4 years ago
Directions: Select ALL the correct answers.
nordsb [41]
Definitely D. The brakes on a bike rub against the wheel. Not sure about the others.
5 0
3 years ago
Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
erica [24]

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

5 0
3 years ago
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