First its ... higher energy of reactants , higher energy of products & you do the same with the lower ones than you do transition state
Answer:
1.06 V
Explanation:
The standard reduction potentials are:
Ag^+/Ag E° = 0.7996 V
Ni^2+/Ni E° = -0.257 V
The half-cell and cell reactions for Ni | Ni^2+ || Ag^+ | Ag are
Ni → Ni^2+ + 2e- E° = 0.257 V
<u>2Ag^+ 2e- → 2Ag </u> <u>E° = 0.7996 V
</u>
Ni + 2Ag^+ → Ni^2+ + 2Ag E° = 1.0566 V
To three significant figures, the standard potential for the cell is 1.06 V
.
Answer:
a. 53.5 g/mol
b. 80.06 g/mol
c. 133.33 g/mol
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Molar Mass - 1 mol per <em>x</em> grams substance
Explanation:
<u>Step 1: Define</u>
a. NH₄Cl
b. NH₄NO₃
c. AlCl₃
<u>Step 2: Find masses</u>
Molar Mass of N - 14.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Al - 26.98 g/mol
Molar Mass of Cl - 35.45 g/mol
<u>Step 3: Calculate compound masses</u>
Molar Mass of NH₄Cl - 14.01 g/mol + 4(1.01 g/mol) + 35.45 g/mol = 53.5 g/mol
Molar Mass of NH₄NO₃ - 2(14.01 g/mol) + 4(1.01 g/mol) + 3(16.00 g/mol) = 80.06 g/mol
Molar Mass of AlCl₃ - 26.98 g/mol + 3(35.45 g/mol) = 133.33 g/mol
Answer: The product from the reduction reaction is
CH3-CH2-CH(CH3)-CH2-CH2OH
IUPAC name; 3- Methylpentan-1-ol
Explanation:
Since oxidation is simply the addition of oxygen to a compound and reduction is likewise the addition of hydrogen to a compound.
Therefore, hydrogen is added onto the carbon atom adjacent to oxygen in 3- methyl pentanal
CH3 CH2 CHCH3 CH2 CHO thereby -CHO( aldehyde functional group) are reduced to CH2OH ( Primary alcohol) which gives;
3-methylpenta-1-ol .
The structure of the product is:
CH3-CH2-CH(CH3)-CH2-CH2OH
