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amm1812
3 years ago
15

Rom a game design perspective, including some risks in your game can help make it both exciting and challenging, but also what e

lse?
A.
humorous

B.
frustrating

C.
confusing

D.
rewarding
Computers and Technology
1 answer:
wolverine [178]3 years ago
8 0

Answer:

Depends on the player base

Explanation:

I would say rewarding to be honest because people like rewards and if they look cool people might play even at their bedtime but humorous might make players play the game more to see the jokes but I kind of doubt it, frustrating... they either rage or try to beat the quest or whatever it is to flex or something I don't know and confusing, like the frustrating one but people are into mystery so I think C would be better then B but I don't know about the other 2 so In my opinion I would say D

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Nat2105 [25]

Answer and Explanation:

Given that total number of records in a file = 100000

Each record consists of= 240 bytes

Given that B= 2400 bytes.

Then total blocks in file = 100000 records * 240 / 2400

= 10000 blocks.

Time that will take for exhaustive read

= s + r + b.btt

= 16 + 8.3 + (10000) * 0.8

= 8024.3 msec

Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.

Hence, X (s + r + btt) > 8024.3

X (16+8.3+0.8) > 8024.3

X > 8024.3/25.1

So that, X > 319.69

Hence, atleast 320 random reads should be made to search the file

8 0
3 years ago
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cricket20 [7]

The Rudolph Rule states that  simple ways you can make information stand out and guide or satisfy your audience to important details and highlight important  information in your presentation

so i conclude option D is correct for above statement

hope it helps

5 0
3 years ago
Read 2 more answers
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Andru [333]

Answer:

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Explanation:

3 0
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jolli1 [7]

Answer:

class OddNumber

{

  public static void main(String args[])  

       {

         int n = 1000;  //Store 1000 in Variable n typed integer

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         for (int i = 1; i <= n; i++)  //For loop to go through each number till end

          {

            if (i % 2 != 0)  //check if number is even or odd.Not divisible by 2 without reminder means it is odd number

             {

               System.out.print(i + " "); //print odd numbers

             }

          }

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}              

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Answer:

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Explanation:

hope this helps

8 0
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