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Natali [406]
3 years ago
15

Exactly 5000 mL of air at 223K is warmed and has a new volume of 8.36 liters. What is the new temperature?

Chemistry
1 answer:
34kurt3 years ago
7 0

Answer:

The new temperature is 373 K

Explanation:

Step 1: Data given

Volume air = 5000 mL = 5.0 L

Temperature = 223K

New volume = 8.36 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒V1 = the initial volume = 5.0 L

⇒T1 = the initial temperature = 223 K

⇒V2 = the new volume = 8.36 L

⇒T2 = the new temperature

5.0/223 = 8.36 /T2

T2 = 373 K

The new temperature is 373 K

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A compound has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen.
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The molecular formula of the compound that has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen is C2H6O2.

<h3>How to calculate molecular formula?</h3>

The molecular formula can be calculated from the empirical formula. The empirical formula of the compound is calculated as follows:

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Next, we convert the mass to moles by dividing by their atomic mass:

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Hence, the empirical formula of the compound is CH3O

If the molar mass of the compound is 62g/mol;

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Therefore, the molecular formula of the compound that has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen is C2H6O2.

Learn more about molecular formula at: brainly.com/question/14425592

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Oxidation half reaction: Zn⁰ → Zn²⁺ + 2e⁻.

Reduction half reaction: Cu²⁺ + 2e⁻ → Cu⁰.

In other chemical reactions, there is no change of oxidation number of elements.

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Oxidizing agent is a substance that has the ability to oxidize other substances, to cause them to lose electrons.

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