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Aleksandr-060686 [28]
3 years ago
8

During the process of sublimation,

Chemistry
1 answer:
Len [333]3 years ago
5 0
During this process. A. Solid turns directly into a Gas.
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What is the best definition for the atomic number in an element
arlik [135]
The atomic number in an element is usually how many protons the element has. For example, Hydrogen has a 1 on top of the H (on the periodic table), therefore, Hydrogen has 1 proton. Oxygen has an 8 on top of the O (on the periodic table) so therefore, Oxygen has 8 protons.
7 0
3 years ago
A filament for a light bulb needs to conduct electricity. Which of the elements listed below might be useful as a light bulb fil
horrorfan [7]

Answer:

A. tungsten

Explanation:

Tungsten is a material which high melting point ie. does not melt easily incase of high temperature

8 0
3 years ago
Read 2 more answers
Write a balanced half-reaction for the oxidation of aqueous hydrazine N2H4 to gaseous nitrogen N2 in basic aqueous solution
Zigmanuir [339]

Answer:

N2H2(aq) + 2OH^-(aq) ----------> N2(g) + 2H2O(l) + 2e

Explanation:

Hydrazine is mostly used in thermal engineering as an anticorrosive agent. Hydrazine can be oxidized in aqueous solution as shown in the equation above. Oxidation has to do with loss of electrons and increase in oxidation number.

The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.

7 0
3 years ago
A chlorine atom has a diameter of 175 picometers (pm). Please write the diameter, in metered, in scientific notation.
IrinaVladis [17]
The answer is 1.75 x 10¹⁰ m.
Scientific notation<span> refers to a mathematical expression that is  used to represent a decimal number between 1 and 10 multiplied by ten, or we can say that to write a large numbers using less digits. 
Diameter of chlorine atom = </span><span>175 picometers (pm) 
</span>175 pm = <span>0.000000000175 m
in scientific notation we will write </span>0.000000000175 m as <span>1.75 x 10</span>¹⁰ m
8 0
3 years ago
What is the vapor pressure of a liquid at 305.03 K if its ∆Hvap = 28.9 kJ/mol and its normal boiling point is 341.88 K?
ASHA 777 [7]

<u>Answer:</u> The vapor pressure of the liquid is 0.293 atm

<u>Explanation:</u>

To calculate the vapor pressure of the liquid, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm

P_2 = pressure of the liquid = ?

\Delta H_{vap} = Heat of vaporization = 28.9 kJ/mol = 28900 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 341.88 K

T_2 = final temperature = 305.03 K

Putting values in above equation, we get:

\ln(\frac{P_2}{1})=\frac{28900J/mol}{8.314J/mol.K}[\frac{1}{341.88}-\frac{1}{305.03}]\\\\\ln P_2=-1.228atm\\\\P_2=e^{-1.228}=0.293atm

Hence, the vapor pressure of the liquid is 0.293 atm

5 0
3 years ago
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