The acceleration is -1.111 m/s²
Explanation:
In this case acceleration is calculated as change in velocity divided by time.
Change in velocity is 20m/s-120 m/s = -100 m/s
Time is 1.5 minutes------change it to seconds by multiplying 1.5 by 60 seconds
Acceleration will be : -100 m/s / (1.5*60) = -1.111 m/s²
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Keywords : object, travel, straight path, velocity, decelerate, acceleration
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Locke said that under natural law, all people have the right to life, liberty, and private property; under the social contract, the people could instigate a revolution against the government when it acted against the interests of citizens, to replace the government with one that served the interests of citizens.
Answer:
x = 129.9 m
y = 30.9 m
Explanation:
When an object is thrown into the air under the effect of the gravitational force, the movement of the projectile is observed. Then it can be considered as two separate motions, horizontal motion and vertical motion. Both motions are different, so that they can be handled independently.
Given data:
= 50 m/s
Angle = 30°
Time = t = 3 s
horizontal component of velocity = 
= cos30°
= 50cos30°
= 43.3 m/s
Vertical component of velocity = 
= Sin30°
= 50Sin30°
= 25 m/s
This is a projectile motion, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.
But the vertical component of velocity varies with time and there is an acceleration along vertical direction which is equal to gravitational acceleration g.
Horizontal distance = x = t
x = 43.3*3
x = 129.9 m
Vertical Distance = y = t -0.5gt²
y = 25*3 - 0.5*9.8*3²
y = 75 - 44.1
y = 30.9 m
Since there are no choices given, I will explain the cycle of a star. The beginning development of a
star is marked by a supernova explosion, with the gases present in the nebula
being forced to scatter. As the star shrinks, radiation of the surface
increases and create pressure on the outside shell to push it away and forming
a planetary nebula or white dwarf. <span>The star is a ball of hot gases containing different kinds of
elements at different cores. It has a very high temperature that radiates all
throughout the Milky Way galaxy. The star has four main parts; the core,
photosphere, chromospheres and corona. The outer core of a star located at the
chromospheres contains mostly of hydrogen. Inside the hydrogen is helium then
carbon, oxygen, neon, magnesium silicon and the inert gas. When a star releases
energy it is due to the thermonuclear fusion of hydrogen into helium. </span>
It is very difficult for an atom to accept a proton. It can only be done under very special circumstances. So A and C are both incorrect. I don't see how D is possible. The atom does lose 1 electron, but how it gets 21 is think air.
The answer is B which is exactly what happens.
