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3 years ago

The symbol or variable to used find initial velocity is

Physics

2 answers:

OleMash [197]3 years ago

7 0

Answer:

v down exponenet 1 brainlest

Explanation:

Veseljchak [2.6K]3 years ago

3 0

Answer:

v0 [vee nought] is the initial velocity when time=0

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What is the kinetic energy of a 2000 kg car moving at 72 km/h?

gtnhenbr [62]

kinetic energy is given by 1 /2

$\times mass \: \times \: velocity {?}^{2}$ then you have to replace the figures

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4 years ago

A car travels 60 miles in the first 2 hours and 68 miles in the next 2 hours

Gemiola [76]

32miles/hr

Explanation:

Given parameters:

Distance 1 = 60miles

Time 1 = 2hrs

Distance 2 = 68miles

Time 2 = 2hrs

Unknown:

Average speed of the car = ?

Solution:

Average speed is the total distance covered in a particular duration of time.

Average speed = $\frac{total distance}{total time taken}$

Total time taken = time 1 + time 2 = 2hrs + 2hrs = 4hrs

Total distance = distance 1 + distance 2 = 60miles + 68miles = 128miles

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4 years ago

An 8 g bullet leaves the muzzle of a rifle with

Elena-2011 [213]

Answer: 1872 N

Explanation:

This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:

$V^{2}=V_{o}^{2} + 2ad$ (1)

$F=ma$ (2)

Where:

$V=611.9 m/s$ is the bullet's final speed (when it leaves the muzzle)

$V_{o}=0$ is the bullet's initial speed (at rest)

$a$ is the bullet's acceleration

$d=0.8 m$ is the distance traveled by the bullet before leaving the muzzle

$F$ is the force

$m=8 g \frac{1 kg}{1000 g}=0.008 kg$ is the mass of the bullet

Knowing this, let's begin by isolating $a$ from (1):

$a=\frac{V^{2}}{2d}$ (3)

$a=\frac{(611.9 m/s)^{2}}{2(0.8 m)}$ (4)

$a=234013.5063 m/s^{2} \approx 2.34(10)^{5} m/s^{2}$ (5)

Substituting (5) in (2):

$F=(0.008 kg)(2.34(10)^{5} m/s^{2})$ (6)

Finally:

$F=1872 N$

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3 years ago

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kolbaska11 [484]

The answer is attached.

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