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Gnesinka [82]
3 years ago
15

A hanging wire made of an alloy of nickel with diameter 0.19 cm is initially 2.8 m long. When a 59 kg mass is hung from it, the

wire stretches an amount 0.286 cm. A mole of nickel has a mass of 59 grams, and its density is 8.90 g/cm3.
(a) Based on these experimental measurements, what is Young's modulus for this alloy of nickel?
Engineering
1 answer:
Makovka662 [10]3 years ago
4 0

Answer:

Young's modulus for this alloy of nickel is 1.997×10^11 N/m^2

Explanation:

Young's modulus = stress/strain

Stress = Force (F)/Area (A)

F = mg = 59 kg × 9.8 m/s^2 = 578.2 N

A = πd^2/4 = 3.142 × (0.19/100)^2/4 = 2.836×10^-6 m^2

Stress = 578.2/2.836×10^-6 = 2.039×10^8 N/m^2

Strain = extension/length = 2.86×10^-3 m/2.8 m = 1.021×10^-3

Young's modulus = 2.039×10^8/1.021×10^-3 = 1.997×10^11 N/m^2

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Researchers at the University of__________modified the iPhone to allow it to create medical images.
Morgarella [4.7K]

Answer:

B

Explanation:

I'm so sorry if this is wrong. This is what I think it is though, I had a class like this and I think this is what I said.

3 0
3 years ago
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If you have a hole diameter of 0.250 with a tolerance of ±0.005, what are the limits of the hole size?
sleet_krkn [62]

Answer:

The limits of the hole size are;

The maximum limit of the hole diameter 0.255

The minimum limit of the hole diameter = 0.245

Explanation:

Tolerance is a standardized form of language that can be used to define the intended 'tightness' or 'clearance' degree between mating parts in a mechanical assembly process and in metal joining processes such as welding and brazing processes

In tolerancing, the size used in the description of a part is known as the nominal size while allowable variation of the nominal size that will still allow the part to function properly is known as the tolerance

A tolerance given in the form ±P is known as bilateral tolerancing, with the value being added to or subtracted from the nominal size to get the maximum and minimum allowable limits of the dimensions of the nominal size

Therefore;

The given nominal dimension of the hole diameter = 0.250

The bilateral tolerance of the dimension, = ±0.005

Therefore;

The maximum limit of the diameter of the hole = 0.250 + 0.005 = 0.255

The minimum limit of the diameter of the hole = 0.250 - 0.005 = 0.245

7 0
3 years ago
A well-insulated tank in a vapor power plant operates at steady state. Saturated liquid water enters at inlet 1 at a rate of 125
Gekata [30.6K]

Answer:

a) \dot m_{3} = 135\,\frac{lbm}{s}, b) h_{3}=168.965\,\frac{BTU}{lbm}, c) T = 200.829\,^{\textdegree}F

Explanation:

a) The tank can be modelled by the Principle of Mass Conservation:

\dot m_{1} + \dot m_{2} - \dot m_{3} = 0

The mass flow rate exiting the tank is:

\dot m_{3} = \dot m_{1} + \dot m_{2}

\dot m_{3} = 125\,\frac{lbm}{s} + 10\,\frac{lbm}{s}

\dot m_{3} = 135\,\frac{lbm}{s}

b) An expression for the specific enthalpy at outlet is derived from the First Law of Thermodynamics:

\dot m_{1}\cdot h_{1} + \dot m_{2} \cdot h_{2} - \dot m_{3}\cdot h_{3} = 0

h_{3} = \frac{\dot m_{1}\cdot h_{1}+\dot m_{2}\cdot h_{2}}{\dot m_{3}}

Properties of water are obtained from tables:

h_{1}=180.16\,\frac{BTU}{lbm}

h_{2}=28.08\,\frac{BTU}{lbm} + \left(0.01604\,\frac{ft^{3}}{lbm}\right)\cdot (14.7\,psia-0.25638\,psia)

h_{2}=29.032\,\frac{BTU}{lbm}

The specific enthalpy at outlet is:

h_{3}=\frac{(125\,\frac{lbm}{s} )\cdot (180.16\,\frac{BTU}{lbm} )+(10\,\frac{lbm}{s} )\cdot (29.032\,\frac{BTU}{lbm} )}{135\,\frac{lbm}{s} }

h_{3}=168.965\,\frac{BTU}{lbm}

c) After a quick interpolation from data availables on water tables, the final temperature is:

T = 200.829\,^{\textdegree}F

8 0
3 years ago
Read 2 more answers
A beam has been fixed to the floor by the pin at B and the roller at A as shown in figure 1 below.​
ahrayia [7]
What figure below???
3 0
3 years ago
An air conditioning system operating on reversed carnot cycle is required to remove heat from the house at a rate of 32kj/s to m
Brilliant_brown [7]

Answer:

(e) 1.64 kW

Explanation:

The Coefficient of Performance of the Reverse Carnot's Cycle is:

COP = \frac{T_{L}}{T_{H}-T_{L}}

COP = \frac{293.15\,K}{308.15\,K-293.15\,K}

COP = 19.543

Lastly, the power required to operate the air conditioning system is:

\dot W = \frac{\dot Q_{L}}{COP}

\dot W = \frac{32\,kW}{19.543}

\dot W = 1.637\,kW

Hence, the answer is E.

3 0
3 years ago
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