Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>
They are the basic components of life or the basic building blocks of life
Answer:
an atom or molecule with a net electric charge due to the loss or gain of one or more electrons
Answer:
0.65 M
Explanation:
Molarity (M) is the amount of moles of a substance per liter.
In other words, M = moles of substance / liters of solution
Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.
M = moles of NaCl / liters of solution
M = 1.5 mol NaCl / 2.3 L
M = 0.65 mol/L (or 0.65 M)
