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Oksi-84 [34.3K]
2 years ago
9

Which of the following are required for plants to carry out photosynthesis?

Chemistry
1 answer:
Vika [28.1K]2 years ago
3 0

Answer:

Carbon dioxide, water, and sunlight

Explanation:

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How would you prepare a 35 ml solution of 95% (volume/volume solution of ethanol?
Artyom0805 [142]

Explanation:

<em><u>Solutions. 1. If 47 g of KCl dissolved in enough water to give 375 mL of soloution, what is the molarity ... vo volume of solute . ... v/v ethanol, how much 95% v/v ethanol ... prepare 200. mL ...</u></em>

7 0
3 years ago
Round off the following number to 3 digits 34,560​
Vikki [24]

Answer:

3.46x10⁴

Explanation:

Hello,

In this case, we can see that the number 34,560 has five significant figures, it means that if we want to write it with three, we must take the 3, 4 and 5 only. Nevertheless, since the 6 after the five is greater than 5, we can round such five to 6, so we obtain:

346

However, the decimal places cannot get lost, therefore, we move the given thousand  to the three, so the number turns out:

3.46x10⁴

Best regards.

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3 years ago
Question 6 pls I need help this is due in 2 minutes!!..
MAVERICK [17]

Answer:

c

Explanation:

7 0
3 years ago
Read 2 more answers
The standard enthalpy change for the following reaction is 873 kJ at 298 K.
Flura [38]

Answer:  - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

2KCl(s)\rightarrow 2K(s)+Cl_2(g)  \Delta H_1=873kJ

Now we have to determine the value of \Delta H for the following reaction i.e,

K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s) \Delta H_2=?

According to the Hess’s law, if we divide the reaction by half then the \Delta H will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=\frac{1}{2}\times (-873kJ)

\Delta H_2=-436.5kJ

Hence, the value of \Delta H_2 for the reaction is -436.5 kJ.

8 0
3 years ago
“True or False”
Sliva [168]
True, I’m sorry if I’m wrong
3 0
3 years ago
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