Calcium hydroxide, Ca(OH)2, is neutralized by hydrochloric acid, HCl, and the products are calcium chloride and water. You have
1 answer:
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Answer:
0.683 mol
46.3 g
Explanation:
There is some info missing. I think this is the original question.
<em>Boron trifluoride gas is collected at 21.0 °C in an evacuated flask with a measured volume of 50.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.330 atm. Calculate the mass and number of moles of boron trifluoride gas that were collected. Round your answer to 3 significant digits.</em>
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Step 1: Convert the temperature to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 21.0°C + 273.15
K = 294.2 K
Step 2: Calculate the moles of boron trifluoride gas
We will use the ideal gas equation.
Step 3: Calculate the mass of boron trifluoride gas
The molar mass of BF₃ is 67.81 g/mol.
<u>Answer:</u> The pH of the resulting solution will be 3.60
<u>Explanation:</u>
Molarity is calculated by using the equation:
......(1)
We are given:
Molarity of formic acid = 0.100 M
Molarity of potassium formate = 0.100 M
Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
Molarity of KOH = 1.00 M
Volume of solution = 7 mL = 0.007 L
Putting values in equation 1, we get:
The chemical equation for the reaction of formic acid and KOH follows:
I: 0.042 0.007 0.042
C: -0.007 -0.007 +0.007
E: 0.035 - 0.049
Volume of solution = [420 + 7] = 427 mL = 0.427 L
To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:
.......(2)
Given values:
Putting values in equation 2, we get:
Hence, the pH of the resulting solution will be 3.60