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ELEN [110]
4 years ago
7

Calcium hydroxide, Ca(OH)2, is neutralized by hydrochloric acid, HCl, and the products are calcium chloride and water. You have

a sample of calcium hydroxide that you know contains 2.6x1024 hydroxide ions, based on an analysis of the sample. How many grams of HCl are required to react with the available calcium hydroxide?
Chemistry
1 answer:
padilas [110]4 years ago
7 0

n = m/Mr   (n= number of moles of a compound; m= mass of a compound; Mr = formula mass of a compound)

Rearranged: m = nxMr

Using the balanced equation for the reaction; <em>Ca(OH)2 + 2HCl ---> CaCl2 + 2H2O   </em>we can see that there are 2 moles of OH- ions for every 2 moles of HCl and therefore we need to react the same number of moles of HCl as moles of OH- ions:

n, OH- ions = 2.6x10^24 mol

therefore:

n, HCl = 2.6x10^24 mol

Mr, HCl = 36.5 (use periodic table and the molecular masses of each element in the compound to find)

To calculate the mass of HCl needed, we multiply the number of moles of HCl and the Mr of HCl:

(2.6x10^24) x 36.5 = 9.49x10^25 g of HCl is required


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The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.

<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>

The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.

The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.

In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.

Moles = mass/molar mass

molar mass of acetic acid = 62 g/mol

molar mass of water = 18 g/mol

moles of vinegar = 5/62 = 0.08

moles of water = 95/18 = 5.28

total moles = 5.36

Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36

Mole ratio of vinegar to water = 0.015 : 0.985

In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.

Learn more about mole ratio at: brainly.com/question/19099163

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