The elastic potential energy of a spring is given by

where k is the spring's constant and x is the displacement with respect to the relaxed position of the spring.
The work done by the spring is the negative of the potential energy difference between the final and initial condition of the spring:

In our problem, initially the spring is uncompressed, so

. Therefore, the work done by the spring when it is compressed until

is

And this value is actually negative, because the box is responsible for the spring's compression, so the work is done by the box.
The path followed by a projectile is called its <em>trajectory. (C)</em>
In the most common school situation<em> </em>... <u>with</u> gravity but <u>without</u> air resistance, the trajectory of a projectile is the shape of an inverted parabola (nose pointing up). That's the result of constant horizontal velocity and accelerated vertical velocity.
Vs - velocity on beginning
ve - velocity on ending. You've got:

So he needed 4 second.
Answer:
Potential energy of the ball would increase
Explanation:
The formula for potential energy of an object is:
Potential Energy (object) = mass x gravity x height
In your question, the value for height is increased when the object (ball) is placed in a higher position. This creates a net positive change in the right-hand side of the formula and since the value of mass and gravity doesn't change because gravity is a constant (meaning it's always 9.8N/kg) and the mass is said to be kept the same, the ball's potential energy would increase.