hydrogen bonding and ion-dipole
Explanation:
The intermolecular forces the particles of fluoride experiences is an ion-dipole bond, between the water molecules, there are hydrogen bonds.
- An ion-dipole bond is an attractive force between an ion and a polar molecule.
- The fluoride is the anion that is attracted by the positive end of water molecules.
- Water is a polar compound.
- Between the water molecule, there is presence of hydrogen bonds.
- Hydrogen bonds are special dipole - dipole attraction between polar molecules joined to a highly electronegative atom.
- The electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule forms the hydrogen bond.
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Hydrogen bond brainly.com/question/10602513
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I think you are suposse to use coefficients of products and reactents to balance the number of atoms of an element on both sides of a chemical equation
i hope this helps
Number of moles of oxygen = x
number of moles of nitrogen = y
x = 2y
initial pressure, p1 = 0.8 atm
final pressure, p2 = 1.10 atm
At constant volume and temperature p1 / n1 = p2 / n2
=> p1 / p2 = n1 / n2
n1 = x + y = 2y + y = 3y
n2 = 0.2 + 3y
=> p1 / p2 = 3y / (0.2 + 3y)
=> 0.8 / 1.10 = 3y / (0.2 + 3y)
=> 0.8 (0.2 + 3y) = 1.10 (3y)
0.16 + 2.4y = 3.3y
=> 3.3y - 2.4y = 0.16
=> 0.9y = 0.16
=> y = 0.16 / 0.9
=. x = 2*0.16/0.9 = 0.356
Answer: 0.356 moles O2
Answer:
44,901 kilo Joule heat is released when 
grams of ammonia is produced.
Explanation:
Moles of ammonia gas produced :
According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.
So, When 978.235 moles of ammonia gas is produced the energy released will be:
(negative sign indicates that energy is released as heat)
44,901 kilo Joule heat is released when grams of ammonia is produced.
Answer:
Yard . I hope this helped:))
