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2 years ago

what should be the angle between two vectors of same angle so that their resultant is equal to either of them?

Physics

1 answer:

asambeis [7]2 years ago

3 0

So, the angle between two vectors having equal magnitude is equal to 120º.

Explanation:

<h2>:) Correct me if I'm wrong...</h2>

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DaniilM [7]

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3 years ago

a. A lifted parcel of air will be colder (heavier) that the air surrounding it. Because of this fact, the lifted parcel will ten

kvv77 [185]

I think the answer is A because it’s a better explanation

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3 years ago

A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational

a_sh-v [17]

Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

Rock: $F = 49.06N$

Pebble: $F = 29.44N$

(b)Calculate the magnitude of the acceleration of each object when released.

Rock: $a =9.8m/s^{2}$

Pebble: $a =9.8m/s^{2}$

Explanation:

The universal law of gravitation is defined as:

$F = G\frac{m1m2}{r^{2}}$ (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

m1 will be equal to the mass of the Earth $m1 = 5.972×10^{24} Kg$ and since the rock and the pebble are held near the surface of the Earth, then, r will be equal to the radius of the Earth $r = 6371000m$ .

$F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(5.0 Kg)}{(6371000 m)^{2}}$

$F = 49.06N$

Newton's second law can be used to know the acceleration.

$F = ma$

$a =\frac{F}{m}$ (2)

$a =\frac{(49.06 Kg.m/s^{2})}{(5.0 Kg)}$

$a =9.8m/s^{2}$

<em>Case for the pebble </em> $m = 3.0 Kg$ <em>:</em>

$F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(3.0 Kg)}{(6371000 m)^{2}}$

$F = 29.44N$

$a =\frac{F}{m}$

$a =\frac{(29.44 Kg.m/s^{2})}{(3.0 Kg)}$

$a =9.8m/s^{2}$

3 0

3 years ago

Read 2 more answers

How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?

Akimi4 [234]

Answer:19.5 m

Explanation:

Given

coefficient of kinetic Friction $\mu _k=0.10$

Initial speed $u=3.9\ m/s$

Friction is present so it tries to stop to the object and stops it completely after moving certain distance let say s

maximum deceleration provided by friction is

$a_{max}=\mu _k\cdot g$

$a_{max}=0.1\times 3.9=0.39\ m/s^2$

using equation of motion

$v^2-u^2=2 as$

where $v=final\ velocity$

$u=initial velocity$

$a=acceleration$

$s=displacement$

$(0)-(3.9)^2=2\times (-0.39)\times s$

$s=19.5\ m$

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3 years ago

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3 years ago

what should be the angle between two vectors of same angle so that their resultant is equal to either of them?​

what should be the angle between two vectors of same angle so that their resultant is equal to either of them?