Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards
1 answer:
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Answer:
- the power to the air is 850 MW
- mass flow rate of the air is 84577.11 kg/s
Explanation:
Given the data in the question;
Net power generated; = 150 MW
Heat input; = 1000 MW
Power to air = ?
For closed cycles
Power to air Q₀ = Heat input; - Net power generated;
we substitute
Power to air Q₀ = 1000 - 150
Q₀ = 850 MW
Therefore, the power to the air is 850 MW
given that ΔT = 10 °C
mass flow rate of air required will be;
⇒ Q₀ / CpΔT
we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K
we substitute
⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]
⇒ ( 850 × 10³ ) / 10.05
⇒ 84577.11 kg/s
Therefore, mass flow rate of the air is 84577.11 kg/s
Let's convert the speed of the winds into SI units.
We know that
1 miles = 1609 m
1 hour = 3600 s
So, the velocity written in m/s is
We know that
1 miles = 1609 m
1 hour = 3600 s
So, the velocity written in m/s is