Sunlight is the requirement of every single natural process on Earth.
Answer:
Nonmetals lose electrons to gain a negative charge and form anions, whereas metals lose electrons to gain a postive charge and form cations.
Atoms that gain or lose electrons are called ions and can have a negative charge or a postive charge.
Explanation:
Answer:
Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)
In net ionic equation we cancel the ions that have equal moles on both sides so Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.
Explanation:
Net ionic equation:
In net ionic equation we only write the ions that are involved in reaction. If the system have same moles of ions in initial and final stages we cancel them as they have the same amount and are present in ionic form in the reaction medium. To formulate an ionic equation we just cancel the ions which have the same moles in initial and final stages.
Chemical equation:
Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + NaNO₃ (aq)
Balanced chemical equation:
In a balanced chemical equation we write the reactants and products in molecular form with number of moles.
Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + 2NaNO₃ (aq)
Ionic equation:
In ionic equation we write the equation in ionic form. It involves all the ions which will produce when we add any ionic compound in reaction medium.
Pb⁺² +2NO₃⁻¹ + CO₃⁻² + 2Na⁺¹ → PbCO3 (s) + 2NO₃⁻¹ (aq) + 2Na⁺¹ (aq)
Net ionic equation
In net ionic equation we cancel the ions that have equal moles on both sides. As we can see in the above ionic equation that Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.
Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)
Answer:
A
Explanation: the satellite with the smallest mass
Explanation:
Because molarity is classified as moles of solute per liter of water, dilution of the water may result in a reduction of its concentration.
Therefore, because the amount of moles of solute has to be constant for dilution, you will use the molarity and volume of that same target solution to calculate how many moles of solute will be present in the sample of the stock solution that you dilute.
c = 
⇒ n
=
c
⋅ V
= 0.250 M ⋅ 6.00 L =
1.5 moles HCl
Now all you have to do is figure out what volume of 6.0 M stock solution will contain 1.5 moles of hydrochloric acid
c =
V = 
= 
=
0.25 L
Expressed in milliliters, the answer will be
→ rounded to two sig figs
