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yarga [219]
2 years ago
6

cyclopropane is a commonly used anesthetic. If a 2.00 L flask contains 3.11 g of cyclopropane gas at 684 mmHg pressure and 23.0

C, what is the molecular mass of cyclopropane
Chemistry
1 answer:
jeka942 years ago
8 0

Answer:

42.0g/mol

Explanation:

The steps for this question is to use the ideal gas law, and then use n=m/M to find molar mass.

PV = nRT

n= PV/RT

Change 23 degrees to 296.15 K and 684mmHg to kpa

n = (91.1925kpa)(2.00L)/(8.314Lkpa/mol K)(296.15K)

n= 0.074mol

n = m/M

M = m/n

M = 41.98489g/mol

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What does it mean to have high density?
lord [1]

Density describes how compact or concentrated something is. For example, suppose you have two boxes, one large and one small. ... That means the small box has a higher density than the large box. Density also tells how concentrated or crowded something is.


4 0
3 years ago
help asap show work | a gas with a volume of 13L at a pressure of 197 kPA is allowed to expand to a volume of 23L. what is the p
Lera25 [3.4K]

Answer:

<h2>111 kPa</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2 =  \frac{13 \times 197000}{23}  =  \frac{2561000}{23}  \\  = 111347.826...

We have the final answer as

<h3>111 kPa </h3>

Hope this helps you

5 0
3 years ago
Which of the following is NOT a property of an acid?
MrMuchimi

the correct answer is feels slippery

5 0
3 years ago
You have prepared a 1.0 M solution of CaCl2 in the laboratory.
Ratling [72]
It’s C I think and I’m not sure
6 0
3 years ago
If I contain 1.86g of krypton gas in a container with a volume of 17.5 liters and at a temperature of 190F, what is the pressure
butalik [34]

Answer:

P = 0.0373 atm

Explanation:

Given data:

Mass of krypton = 1.86 g

Volume of krypton = 17.5 L

Temperature of krypton = 190 F

Pressure of krypton = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/ molar mass

Number of moles = 1.86 g/ 83.9 g/mol

Number of moles = 0.022 mol

Formula:

PV = nRT

P = nRT / V

P =  0.022 mol × 0.0821 atm. L. mol⁻¹. K⁻¹ × 360.928 K /  17.5 L

P = 0.652 atm. L /17.5 L

P = 0.0373 atm

7 0
4 years ago
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