What are the two distinct ways in which energy moves outward from the solar core to photosphere?

Physics

1 answer:

butalik [34]3 years ago

6 0

Answer:

The energy may be carried in the form of (1) radiation, where energy travels in the form of light, and (2) convection, where energy is carried by physical motion of upwelling solar gas.

Explanation:

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Why is the unit of momentum called derived unit

Mnenie [13.5K]

Answer:

the SI unit of momentum is :- kg.ms-1

and we know that,

kinetic energy = 1/2 mv2

E=p2/2m

p=(2Em)1/2

so the derived units are (J.kg)1/2

Explanation:

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3 years ago

The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)

Nuetrik [128]

<h2>Answer </h2>

Option C - Carbon Dioxide and Water

<u>Explanation </u>

The chemical equation reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O).

CH4 + 2O2 → CO2 + 2H2O.

In this equation, carbon dioxide and water are products. Products are substances which are formed after a chemical reaction so in this case carbon dioxide and water are formed as a result after a chemical reaction. Therefore, these are products of reaction of methane and oxygen gas.

8 0

3 years ago

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A sky diver jumps out of a plane 4000 meters in the air. How fast would he

ddd [48]

Answer:

100 miles per hour

Explanation:

3 0

4 years ago

A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9

Andreyy89

Answer:

$d = 0.0306 m$

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

$U + K = constant$

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

$\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0$