Answer:
The velocity of the collar will be 3.076 ft/s
Explanation:
Given data
weight of the disk, Wa = 20lb
weight of rod BC, Wbc = 4lb
weight of collar, Wc = 1lb
Considering the equation of equilibrium
Vb = 1.5Wbc
Wa = 1.875 Wbc
to calculate the velocity of the collar using energy conservation equation
T1 + V1 = T2 + V2
=>
=>
=>
Wbc = 1.18rad/sec
i.e.
= 3.076 ft/ s
Answer:
<h3>
2.3125m/s²</h3>
Explanation:
Using the equation of motion v² = u²+2aS
v is the final velocity = 120km/hr
120km/hr = 120 * 1000/1 * 3600 = 33.3m/s
u is the initial velocity = 0m/s
a is the acceleration
S is the distance covered = 240m
On substituting the given parameters
33.3² = 0²+2a(240)
33.3² = 480a
1110 = 480a
a = 1110/480
a = 2.3125m/s²
Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²
Constant acceleration is when the velocity changes the same amount in every equal time period. For example : 9.8 m/s^2
Instantaneous acceleration is the rate at which velocity changes at a specific instant in time. For example: at one point it might be 8m/s^2 and at another point 13m/s^2
Answer:
54%
Explanation:
We are given that
S.D=4.2 lb
Mean=
We have to find the percentage of household throw out at least 9 lb of paper a week.
Normal distribution formula :
We have a=9
%
Hence, the percentage of household throw out at least of paper a week=54%
The answer to this question is D
