Answer:
1) Hence, the period is 0.33 s.
2) The amplitude is 10 cm.
Explanation:
1) The period is given by:
Where:
f: is the frequency = 3 bob up and down each second = 3 s⁻¹ = 3 Hz
Hence, the period is 0.33 s.
2) The amplitude is the distance between the equilibrium position and the maximum position traveled by the spring. Since the spring is moving up and down over a distance of 20 cm, then the amplitude is:
Therefore, the amplitude is 10 cm.
I hope it helps you!
Answer: A) Deceleration of the car is -6.6667 m/s² while it came to stop.
B) The total distance the car travels is 200 meter during the 10 s period.
Explanation:
Given Data
Initial velocity of the car () = 20.0 m/s
Final velocity of the car () = 0 m/s
Time (in motion) =7.00 s
Time (in rest) =3 s
To find - A) car's deceleration while it came to a stop
B) the total distance the car travels in 10 s
A) The formula to find the deceleration is
Deceleration = (( final velocity - initial velocity ) ÷ Time) (m/s²)
Deceleration = (() - (
)) ÷ time (m/s²)
Deceleration = ( 0.0 - 20 ) ÷ 3 (m/s²)
Deceleration = (- 20) ÷ 3 (m/s²)
Deceleration = - 6.6667 m/s²
(NOTE : Deceleration is the opposite of acceleration so the final result must have the negative sign)
The car's deceleration is - 6.6667 m/s² while it came to a stop
B) The formula to find the distance traveled by the car is
Distance traveled by the car is equals to the product of the speed and time
Distance = Speed × Time (meter)
Distance = 20.0 × 10
Distance = 200 meters
The total distance the car travels during the period of 10 s is 200 meters