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mart [117]
3 years ago
14

During a race, a dragster is 200m from the finish line when something goes wrong and it stops accelerating. It travels at a cons

tant velocity of 45 m/s for 3 seconds to try to finish the race. How far from the finish line is the dragster after 3 seconds?
Physics
1 answer:
GarryVolchara [31]3 years ago
4 0

Answer:

135 m

Explanation:

Speed = 45 m/s, time = 3 second

The formula for the distance is given by

Distance = speed x time = 45 x 3 = 135 m

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The factors that affects the carrying capacity are the "food availability,  water supply, environmental condition and living space"

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The carrying capacity of an environment varies in different species and there are chances of being change over the time because of the various factors which is like food availability, water supply, environmental condition ad also the living space. The carrying capacity is mostly dependent upon the available resources and also the  services available in the ecosystem. The symbol for the carrying capacity is K. If the population size will increase the carrying capacity are not sustainable and hence it will degrade the habitat.

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0,0 if you’re looking for plot .
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You exert 500 N of force down on the earth as you jump into the air. How much force does the earth exert back on you?
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A uniform wooden plank with a mass of 75kg and length of 5m is placed on top of a brick wall so that 1.5m of plank extends beyon
jek_recluse [69]

Answer:

x₂ = 1.33 m

Explanation:

For this exercise we must use the rotational equilibrium condition, where the counterclockwise rotations are positive and the zero of the reference system is placed at the turning point on the wall

            Στ = 0

            W₁ x₁ - W₂ x₂ = 0

where W₁ is the weight of the woman, W₂ the weight of the table.

Let's find the distances.

Since the table is homogeneous, its center of mass coincides with its geometric center, measured at zero.

           x₁ = 2.5 -1.5 = 1 m

The distance of the person is x₂ measured from the turning point, at the point where the board begins to turn the girl must be on the left side so her torque must be negative

            x₂ = \frac{M_1g  }{m_2 g} \ x_1

           

let's calculate

           x₂ = \frac{100}{75}  \ 1

           x₂ = 1.33 m

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3 years ago
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