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erik [133]
3 years ago
14

Which of the following phenomena best demonstrates that light possesses wave characteristics?

Physics
1 answer:
photoshop1234 [79]3 years ago
5 0
The answer should be c
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What is the kinetic energy of 0.01kg bullet traveling at a velocity of 700m/s ?
Nata [24]

Answer:

kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie.

Explanation:

In the given question, we are told that what is the kinetic energy of mass M equals 0.1 kg bullet traveling at a velocity Velocity is given and 700 m/s. So we know that kinetic energy mm-hmm k equals one half m v squared. So this will be mass is given 0.1 and velocity is 700 so 700 square this is one half 0.1 in two 49 double zero, double zero. This is one-half into 49 double zero. So kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie. This is kinetic energy. Thank you.

5 0
2 years ago
A diagram of a closed circuit with power source on the left labeled 12 V, a resistor on the top labeled 10 Ohms, a resistor on t
zalisa [80]

Answer:

7.5 A

6.0 A

5.0 A

Explanation:

6 0
3 years ago
Read 2 more answers
The flow of electricity in a certain path is called.
JulijaS [17]

The flow of electricity in a certain path is the circuit.

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2 years ago
Learning Goal: To understand the nature of a sound wave, including its properties: frequency, wavelength, loudness, pitch, and t
Lady_Fox [76]

Answer:

Sound wave is a longitudinal wave that propagates in a medium

Explanation:

<em>Part A:</em> (C) Sound wave is propagation of pressure fluctuations in a medium.

<em>Part B: </em>(C) Pressure fluctuations travel along the direction of propagation of         the sound wave.

<em>Part C: </em>(A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.

5 0
3 years ago
For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is
ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)

where A(t)=A₀e^{\frac{-bt}{2m}}

 A₀ is the amplitude at t=0 and

w' is the angular frequency of damped SHM, which is given by,

w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

Now coming to the problem,

Given: m=1.2 kg

           k=9.8 N/m

           b=210 g/s= 0.21 kg/s

           A₀=13 cm

a) A(t)=A₀/8

⇒A₀e^{\frac{-bt}{2m}} =A₀/8

⇒e^{\frac{bt}{2m}}=8

applying logarithm on both sides

⇒\frac{bt}{2m}=ln(8)

⇒t=\frac{2m*ln(8)}{b}

substituting the values

t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)

b) w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }

w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}

T'=\frac{2\pi}{w'}, where T' is time period of damped SHM

⇒T'=\frac{2\pi}{2.86}=2.2s

let n be number of oscillations made

then, nT'=t

⇒n=\frac{24}{2.2}=11(approx)

8 0
3 years ago
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