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2 years ago

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A population has a mean of 200 and a standard deviation of 50. Suppose a simple random sample of size 100 is selected and x is u

sed to estimate . a. What is the probability that the sample mean will be within 65 of the population mean

1 answer:

svlad2 [7]2 years ago

6 0

Answer:

z(195) = (195-200)/50 = -0.1

z(205) = (205-200)/50 = +0.1

P(195 < x < 205) = p(-0.1 < z < 0.1) = 0.0797

Step-by-step explanation:

step by step is in they're

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The sum of two numbers is equal to 11 and the difference is 19. What are the two numbers?

charle [14.2K]

$\bold{\huge{\pink{\underline{ Solution }}}}$

<u>We </u><u>have </u><u>given </u><u>in </u><u>the </u><u>question </u><u>that</u><u>, </u>

<u>The </u><u>sum </u><u>of </u><u>2</u><u> </u><u>numbers </u><u>is </u><u>equal </u><u>to </u><u>1</u><u>1</u><u> </u>
<u>The </u><u>difference </u><u>between </u><u>two </u><u>numbers </u><u>is </u><u>1</u><u>9</u><u> </u><u>.</u>

$\bold{\underline{ To \: Find }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y</u><u>. </u>

$\bold{\underline{ Let's \: Begin }}$

Let the two numbers be x and y

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

$\sf{ x + y = 11......eq(1) }$

$\sf{ x - y = 19......eq(2) }$

<u>Solving </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

$\sf{ x + y = 11 }$

$\sf{ x = 11 - y ......eq(3 ) }$

<u>Subsituting </u><u>eq(</u><u>3</u><u> </u><u>)</u><u> </u><u>in </u><u>eq</u><u>(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ x - y = 19 }$

$\sf{ ( 11 - y) - y = 19 }$

$\sf{ 11 - y - y = 19 }$

$\sf{ 11 - 2y = 19 }$

$\sf{ - 2y = 19 - 11 }$

$\sf{ - 2y = 8}$

$\sf{ y = 8/(-2) }$

$\sf{ y = - 4 }$

$\sf{\red{Thus ,\: the\: value\: of \: y = -4}}$

<u>Now</u><u>, </u><u> </u><u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>3</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ x = 11 - y }$

$\sf{ x = 11 - (-4 ) }$

$\sf{ x = 11 + 4 }$

$\sf{ x = 15 }$

Hence, The value of x and y are 15 and (-4) .

5 0

3 years ago

Can someone help me pls

rodikova [14]

Answer:

C. 1/3x + 5

Step-by-step explanation:

Plugging in the values for x, we get:

y = 1/3(0) + 5 = 5

y = 1/3(6) + 5 = 7

y = 1/3(12) + 5 = 9

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I almost broke my neck trying to read this problem. :(

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3 years ago

Express in logarithmic form for the base. x y = P

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So

$x^y=P$

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basically, the power that a must be raised to to obtain c is b

so
$x^y=P$ translates to $log_x(P)=y$

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