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3 years ago

Need immediate help!!!

Chemistry

1 answer:

Fantom [35]3 years ago

4 0

Answer:

brainlest= help you

Explanation:

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Trava [24]

Answer: 2.52 M

Explanation:

The product of molarity (moles/litre) and volume in litres yields moles, and the numbers of moles in two solutions means dilute and concentrated are equal, which is expressed by the following equation:

$M_1V_1=M_2V_2$

$$Given that\\M $1=12.0 \mathrm{M}$ or mole $/ \mathrm{L}$\\$\mathrm{V} 1=420 \mathrm{ml}$\\$\mathrm{M} 2=$ ?\\$\mathrm{V} 2=2.0 \mathrm{~L}$ or $2000 \mathrm{ml}$\\\\$\mathrm{M} 1 \mathrm{~V} 1=\mathrm{M} 2 \mathrm{~V} 2$\\$\mathrm{M} 2=\mathrm{M} 1 \mathrm{~V} 1 / \mathrm{V} 2$\\$=12.0 * 420 / 2000$\\$=2.52 \ \mathrm{M}$

3 0

2 years ago

What’s the difference between attractive forces and covalent bonds

Scrat [10]

Answer:

An intramolecular force is between that atoms makeup a molecule. An intermolecular force is between entire molecules. A non-polar covalent bond occurs when the electrons are equally shared between atoms.

3 0

2 years ago

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From which source is pomace derived? (1 point)

GrogVix [38]

Answer: unused waste from food processing

Explanation: have you takin the chemical reaction system unit test yet? It’s alternated

6 0

3 years ago

What is the pH of a 5.09 x 10-5 M solution of NaOH?

Varvara68 [4.7K]

Answer: The pH of the solution is 9.71

Explanation:

1 mole of NaOH produces 1 mole of sodium ions and 1 mole of hydroxide ions.

We are given:

pOH of the solution = 7.2

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOh of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=5.09\times 10^{-5}M$

Putting values in above equation, we get:

$pOH=-\log(5.09\times 10^{-5})\\\\pOH=4.29$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH=14-4.29=9.71$

Hence, the pH of the solution is 9.71

7 0

3 years ago

According to their locations on the Periodic Table, argon (Ar) and neon (Ne) are

a_sh-v [17]

Your answer would be (D), Noble Gases, or Inert Gases - The far right on the periodic table is also known as Group(0)., or Group 18 on the periodic table. Elements in this group includes, Neon(NE), Argon(AR), Krypton(KR), Xenon(XE), and Radon(RN).

Hope that helps!!!

3 0

3 years ago

Read 2 more answers