Need immediate help!!!

Identify which of the following descriptions of a tree is quantitative?

sattari [20]

Answer:

b) has leaves that are 8 -10 cm long

8 0

2 years ago

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The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351

ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of $N_2$ and $H_2$ by using ideal gas equation.

For $N_2$ :

$PV_{N_2}=n_{N_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $N_2$ gas = 1580 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{N_2}=70.49mole$

For $H_2$ :

$PV_{H_2}=n_{H_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $H_2$ gas = 3510 L

n = number of moles $H_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{H_2}=156.6mole$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 3 mole of $H_2$ react with 1 mole of $N_2$

So, 156.6 moles of $H_2$ react with $\frac{156.6}{3}\times 1=52.2$ moles of $N_2$

From this we conclude that, $N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of $N_2$ reactant (unreacted gas).

Excess moles of $N_2$ reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

$PV=nRT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K$

$V=409.9L$

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0

3 years ago

Which best describes the functional group in an aldehyde?

aniked [119]

C. a carbon chain with a carbonyl group bonded to one end

3 0

3 years ago

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48,000,000,000 g scientific notation

sineoko [7]

Answer:

We want to express it in scientific notation.

We will count how many places to the left we move
We utilize scientific notation to simplify calculation
Hence we move 10 to the left
Our answer is 4.8 × 10^10

3 0

3 years ago

B.) If the half-life of Carbon-14 is 5230 years and I start with 100 grams, how long will it take for the

irina1246 [14]

Answer:

26150 years

Explanation:

First we need to determine the number of half lives -- not years -- it'll take for 100g (of any element) to decay to 3.125 g

First Half Life 100/2 = 50

Seconf Half Life 50/2 = 25

Third Half Life 25/2 = 12.5

Fourth Half Life 12.5/2 = 6.25

Fifth Half Life 6.25/2 = 3.125

So it'll take 5 half lives for 100g to decay to 3.125g.

If the Half Life of Carbon-14 is 5230 and it will take 5 half lives, to determine the number of years we just need to multiply 5*5230

5*5230 = 26150

This means that it will take 26150 years for 100g Carbon-14 to decay to 3.125g.

Hope this helps!

8 0

3 years ago