A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to −10.0°C as it releases 543

Question

NISA [10]

3 years ago

8

A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to −10.0°C as it releases 543

J of energy. What is the mass of the sample? Round your answer to three significant figures.

Chemistry

2 answers:

Andreas93 [3] · Answer 1 · 2021-12-04T06:11:57+03:00

Andreas93 [3]3 years ago

8 0

We know, Q = m.c.Δt
m = Q / c.Δt

Here, Q = 543 J
c = 0.227 J/g C
Δt = 15-(-10) = 25 C

Substitute their values,
m = 543 / 0.227 * 25
m = 543 / 5.675
m = 95.68 g

In short, Your Answer would be 95.68 gram

Hope this helps!

pshichka [43] · Answer 2 · 2021-12-04T07:48:42+03:00

pshichka [43]3 years ago

8 0

Answer:

see attached picture

Explanation: