Molarity of solution is expressed as,
Molarity =

Molecular weight of KCl = 74.55 g/mol
For preparing 1 mol of KCl solution (1 liter), 74.44 g KCl must be dissolved in 1 liter of water.
Following glasswares are required for preparing the solution.
1) Watch Glass (for weight the KCl)
2) Beaker (for preparing the solution)
3) Stirrer (For dissolving KCl in water)
4) Standard measuring flask (To ensure final volume of solution is 1 liter)
I found a similar question online which will help me answer your incomplete question. To make it easier, show all the elements of the compound given. It is shown in the second picture attached.
a.) The formula for unsaturation number is shown in the 3rd picture attached. Following this,
n = 8
m = 2(8) + 2 + 0 + 0 - 0 = 18
Thus,
x = Unsaturation number = (18 - 8)/2 = 5
<em>The unsaturation number is 5.</em>b.) The molar mass of C is 12.01 g/mol; H is 1 g/mol; O is 16 g/mol. So, the molecular weight is:
Molecular weight = 12.01(8) + 8(1) + 2(16) = 136.08 g/mol
<em>The molecular weight of the ester is 136.08 g/mol.</em>
Answer:
THE MOLARITY OF SULFURIC ACID SOLUTION IS 0.05 L
Explanation:
Ca Va = Cb Vb
Ca = ?
Va = 75.0mL = 0.075 L
Cb = 0.150 M
Vb = 25.0 mL = 0.025 L
Ca = CbVb/ Va
Ca = 0.150 * 0.025 / 0.075
Ca = 0.00375 / 0.075
Ca = 0.05 M
The molarity is 0.05 L
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