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butalik [34]
3 years ago
11

On the periodic table, what is a group? For the main groups, what characteristic

Chemistry
1 answer:
rjkz [21]3 years ago
4 0
<h3>Answer: Mendeleev’s Periodic Table was built by listing the known elements in order of increasing atomic mass and grouping the elements by their properties (such as reactivity and formula of oxides). In one or two cases, he discovered that he had to put a lower atomic mass element after a higher atomic mass element because the table which went strictly by increasing atomic mass produced groups with inconsistent properties. He also left blanks in the table.</h3>

In modern times, we know that the elements in a given group (also known as a family or column) have the same number of valence electrons, with ground state configurations having a consistent pattern, for instance:

F 1s2 2s2 2p5, Cl 1s2 2s2 2p6 3s2 3p5, Br 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5, etc.

Of course, the ground state configurations play a major role in determining how an element reacts and what compounds it forms. Thus, the elements in a given group have similar properties.

The structure of the table also predicts how the properties vary. For instance, atomic radius increases down a group as does metallic character.

<h3>Hope this helps have a awesome day/night✨</h3>

Explanation:

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A 40.0 milligram sample of 33p decays to 10.0 milligrams in 50.0 days. What is the half life of 33p?
il63 [147K]

Answer:

half life = 25 days

Explanation:

Given data:

Total amount of sample = 40 mg

Sample left after 50 days = 10 mg

Half life of P³³ = ?

Solution:

<em>1st step:</em>

when time is zero = 40 mg

1 half life = 40/2 = 20 mg

2 half life = 20/ 2= 10 mg

<em>2nd step:</em>

<em>Elapsed time/ half life = HL</em>

half life = 50 days/ 2

half life = 25 days

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3 years ago
t the R group in the reagent over the arrow be isopropyl. (i.e. The reagent is LiN[CH(CH3)2]2.) Now, fill in the blanks. This re
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Answer:c. Hofmann's; less

Explanation:

The Hofmann elimination process, named after its discoverer, the German chemist August Wilhelm Von Hofmann rule states that the major alkene product is the <u>least substituted </u>and least stable product when it comes to asymmetrical amines.  The Hofmann elimination can be illustrated in t e formation of “Hoffman” products in elimination reactions  using a less common, LDA LiN[CH(CH3)2]2  Lithium Di-isopropyl Amide (LDA) usually with base  potassium t-butoxide  which will give rise to a less substituted alkene.

This reaction will follow Hofmann's_____ rule and will form the ___less______ substituted alkene.

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3 years ago
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5. If you evaluated 5 solvents as possible recystallization solvents do you think it is generally true that the solvent which ap
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Answer:

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Explanation:

4 0
3 years ago
What amounts of sodium benzoate would be required to prepare 2.5L of 0.35M benzoic buffer solution with a pH of 6.10? Ka of benz
slava [35]

Answer:

Benzoic acid: 1.288g

Sodium benzoate: 124.48g

Explanation:

Benzoic acid, HC7H5O2 is in equilibrium with its conjugate base, C7H5O2⁻ producing a buffer. The pH of the buffer can be determined following H-H equation:

pH = pKa + log [C7H5O2⁻] / [HC7H5O2] (1)

<em>Where pH is desire pH = 6.10 pKa is -log Ka = 4.187 and [] are molar concentrations of the buffer.</em>

As you want to prepare 2.5L of a 0.35M of buffer, moles of buffer are:

2.5L ₓ (0.35mol / L) = 0.875moles of buffer.

And you can write:

0.875 moles = [C7H5O2⁻] + [HC7H5O2] (2)

Replacing (2) in (1)

pH = pKa + log [C7H5O2⁻] / [HC7H5O2]

6.10 = 4.187 + log [C7H5O2⁻] / [HC7H5O2]

1.913 =  log [C7H5O2⁻] / [HC7H5O2]

81.846 = 0.875mol - [HC7H5O2] / [HC7H5O2]

81.846 [HC7H5O2] = 0.875mol - [HC7H5O2]

82.846 [HC7H5O2] = 0.875mol

<h3>[HC7H5O2] = 0.01056 moles</h3>

And moles of the benzoate, [C7H5O2⁻]:

[C7H5O2⁻] = 0.875mol - 0.01056mol =

<h3>[C7H5O2⁻] = 0.8644mol</h3><h3 />

Using molar mass of benzoic acid and sodium benzoate, amount of each compound you must add to prepare 2.5L of the buffer are:

Benzoic acid: 0.01056mol ₓ (122.01g/mol) = 1.288g

Sodium benzoate: 0.8644mol ₓ (144.01g/mol) = 124.482g

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I think it’s lysosomes
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