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Natali [406]
2 years ago
11

Is there a relationship between the distance and the sum? Is there a relationship between the distance and the difference?

Mathematics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

no idea

Step-by-step explanation:

but God bless you my boi

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Five plus 4 times a number is equal to the sum of 7 times the number and 11.
wel
The equation would be 5+4x=7x+11
Which comes out to:
x = - 2
6 0
3 years ago
Read 2 more answers
Janine is analyzing spending habits of students in her high school. She finds a mean monthly discretionary expense of $70 spent
aliina [53]

Answer:

Variance = 25

Step-by-step explanation:

<em>Standard deviation is the under root of variance.</em>

<em>Variance is the square of standard deviation.</em>

<u>Data:</u>

Mean = 70

Variance = ?

Standard deviation = √variance = 5

Variance = 5²

Variance = 25.

Therefore, the variance is 25.

3 0
4 years ago
X^2-3x+2 is a standard or not standard from
NemiM [27]
It’s standard form
standard form is generally ax^2+bx+c
5 0
4 years ago
2. The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4.5. Suppose we going t
stiv31 [10]

Answer:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable who represent the score of golfers. We select a sampel size of 81.

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X>76)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 76 we got:

z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2

And if we use the complement rule and the normal standard distribution or excel we got:

P(Z>2) = 1-P(Z

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

6 0
3 years ago
Chaz bought 4 baseball cards for $2 each and 8 baseball cards for $3 each. Simplify the expression to find the amount Chaz spent
Murljashka [212]
The answer you will get when you multiple and add is 32

8 0
3 years ago
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