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3 years ago

What is the speed of an electromagnetic wave with a frequency of 100 mhz as it travels through a vacuum?

Physics

1 answer:

SCORPION-xisa [38]3 years ago

6 0

Answer:

The speed of the wave with a frequency 100 mhz will be $3\times 10^{8}m/sec$

Explanation:

We have given that frequency of light is 100 mhz

We have to find the speed of light in vaccuum

We know that all electromagnetic waves travels in vaccum wth the same speed as the speed of light

And we know that speed of light is equal to $3\times 10^{8}m/sec$

So the speed of the wave with a frequency 100 mhz will be $3\times 10^{8}m/sec$

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True or false. electrons move in orbits in the same way plants orbit the sun

zalisa [80]

One plants don't orbit the sun, the earth does.
two true if its saying plants orbit the sun

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3 years ago

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What do we call a substance in which two or more elements are chemically bonded

Goryan [66]

Answer:

A compound

Explanation:

A compound is a substance formed when two or more elements are chemically joined

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3 years ago

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A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−

Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ .

Explanation:

Given that,

The actual wavelength of the hydrogen atom, $\lambda_a=5.13\times 10^{-7}\ m$

A hydrogen atom in a galaxy moving with a speed of, $v=6.65\times 10^6\ m/s$

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

$v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}$

$\lambda_o$ is the observed wavelength

$\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m$

So, the observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ . Hence, this is the required solution.

8 0

3 years ago

A ball initially at rest rolls down a hill with an acceleration of 3.3 m/s2. If it accelerates for 7.5 s, how far will it move?

goldfiish [28.3K]

Answer:

Ball will move 92.8125 meter along the cliff in 7.5 seconds.

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case initial velocity = 0 m/s, acceleration = 3.3 $m/s^2$ , we need to calculate displacement when time = 7.5 seconds.

Substituting

$s=0*7.5+\frac{1}{2} *3.3*7.5^2\\ \\ =92.8125 meter$

So ball will move 92.8125 meter along the cliff in 7.5 seconds.

5 0

3 years ago

A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.85 m/s2

Tasya [4]

Answer:

Coefficient of friction = 0.836

Explanation:

If v be the speed after one quarter of the circular path

v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8

tangential acceleration = 5.8 m/s²

radial acceleration = v² /r = 5.8

total acceleration = √2 x 5.8

m x√2 x 5.8 = m x g xμ

μ = √2 x 5.8 / 9.8 = 0.836

7 0

3 years ago