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3 years ago

in a cricket match there are 5000 spectators counted 10 by 10 the number of significant figure in the measurement will be

Physics

1 answer:

BabaBlast [244]3 years ago

8 0

Answer:

$\boxed{3 \ Significant \ figures}$

Explanation:

Total spectators = 5000

Counted by the groups of ten, So at last the result will be:

=> 5000/10 = 500

Significant figures in 500 are 3

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a raft of dimensions 2m wide by 3m long by .5m thick is floating in a pond if one fourth of the raf is submerged find the densit

11111nata11111 [884]

Answer:

250 kg/m3

Explanation:

The total volume of the raft is length times width times height

V = lwh = 2 * 3 * 0.5 = 3 m cubed

The volume of the raft that is submerged in water is 1/4 of total volume

3 /4 = 0.75 m cubed

Let water density = 1000 kg/m cubed and g = 10 m/s2

The buoyant force is equal to the weight of water displaced by the raft

F = 0.75 * 1000 * 10 = 7500 N

This force is balanced by the raft weight, so the weight of the raft is also 7500N

Mass of raft is 7500 / g = 7500 / 10 = 750 kg

Raft density is mass divided by volume = 750 / 3 = 250 kg/m3

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3 years ago

A paper clip is pushed horizontally off a table with speed 1.5m/s. If the table has a height of 1.1m how far from the table does

Julli [10]

the answer is D. 0.71 m

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3 years ago

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Please i need the answer of this question

frez [133]

Answer:

i think it is f i could be wrong-

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3 years ago

the skid marks left by the decelerating jet-powered car the spirit of america were 9600 m long before it came to a stop at 198 m

N76 [4]

Answer:

97 s

Explanation:

Given:

Δx = 9600 m

v₀ = 198 m/s

v = 0 m/s

Find: t

Δx = ½ (v + v₀) t

9600 m = ½ (0 m/s + 198 m/s) t

t = 97 s

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3 years ago

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An alpha particle (charge +2e) and an electron move in opposite directions from the same point, each with the speed of 2.80×10^5

Evgesh-ka [11]

Answer:

Explanation:

Magnetic field due to moving charge =

$B=\frac{\mu_0}{4\pi} \times \frac{qv}{r^2}$

q is charge moving with velocity v and r is distance from point at which field is calculated .

For alpha particle

$B_1=\frac{\mu_0}{4\pi} \times \frac{2\times 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}$

= 0.1316 x 10⁻³ T

For electron

$B_2=\frac{\mu_0}{4\pi} \times \frac{ 1.6\times10^{-19}\times 2.8\times 10^5}{(8.25\times 10^{-9})^2}$

= .0658 x 10⁻³ T .

Both these magnetic field will be same in direction because direction of equivalent current is same for both the particles .

Hence

Total magnetic field

= B₁ + B₂ = .1974 x 10⁻³

= 1.974 x 10⁻⁴ T .

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3 years ago