The correct answer is making observations in his experiment.
In his cathode ray tube experiment J. J. Thomson proved that the cathode rays are indeed negatively charged particles. He then went on to calculate charge-to-mass ratio of the electron. J. J. Thomson’s pioneering work lest to the theory that the atomic structure is made up of charged particles.
Can you provide a picture
Because we are moving at a constant rate (seeing as we're on earth and the earth is spinning) but the moon does not spin as it revolves around us, therefore we only see the one side of it.
Answer: Km = 10μM
Explanation: <u>Michaelis-Menten constant</u> (Km) measures the affinity a enzyme has to its substrate, so it can be known how well an enzyme is suited to the substrate being used. To determine Km another value associated to an eznyme is important: <em>Turnover number (Kcat)</em>, which is the number of time an enzyme site converts substrate into product per unit time.
Enzyme veolcity is calculated as:
![V_{0} = \frac{E_{t}.K_{cat}.[substrate]}{K_{m}+[substrate]}](https://tex.z-dn.net/?f=V_%7B0%7D%20%3D%20%5Cfrac%7BE_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D%7D%7BK_%7Bm%7D%2B%5Bsubstrate%5D%7D)
where Et is concentration of enzyme catalitic sites and has to have the same unit as velocity of enzyme, so Et = 20nM = 0.02μM;
To calculate Km:
![V_{0}*K_{m} + V_{0}*[substrate] = E_{t}.K_{cat}.[substrate]](https://tex.z-dn.net/?f=V_%7B0%7D%2AK_%7Bm%7D%20%2B%20V_%7B0%7D%2A%5Bsubstrate%5D%20%3D%20E_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D)
![K_{m} = \frac{E_{t}.K_{cat}.[substrate]-V_{0}*[substrate]}{V_{0}}](https://tex.z-dn.net/?f=K_%7Bm%7D%20%3D%20%5Cfrac%7BE_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D-V_%7B0%7D%2A%5Bsubstrate%5D%7D%7BV_%7B0%7D%7D)

Km = 10μM
<u>The Michaelis-Menten for the substrate SAD is </u><u>10μM</u><u>.</u>