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4 years ago

Can someone answer #4.

Physics

1 answer:

gtnhenbr [62]4 years ago

8 0

A because the ball is moving up (kinetic) and the higher it goes the greater the potential energy when it'll fall.

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What maximum upward acceleration can it give the elevator without breaking?.

MariettaO [177]

The maximum upward acceleration that the elevator can have without breaking is = 10.36m/s².

<h3>How to calculate maximum upward acceleration?</h3>

To calculate the maximum acceleration of the elevator we must take into account Newton's second law and its formula that takes into account the following aspects:

F = Is the force applied in newtons.
m = Is the mass of the object in kilograms.
a = Is the acceleration of the object in meters per second squeared.

F = m × a

According to the above, we apply the values we have as follows:

a = $\frac{F}{m}$

a = $\frac{21750N}{2100Kg}$

a = 10.36 m/s²

Note: This question is incomplete because some information is missing. Here is the complete information.

Learn more about acceleration in: brainly.com/question/13312735

7 0

3 years ago

When an object is moving with uniform circular motion, the centripetal acceleration of the object a. is circular. b. is perpendi

never [62]

Hi Pupil Here's Your answer :::

➡➡➡➡➡➡➡➡➡➡➡➡➡

When an object is moving with uniform circular motion, the centripetal acceleration of the object $\textbf{is\:Zero}$ .

Because the body is moving with a uniform velocity and hence, there might not be any acceleration due to it.

⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅

Hope this helps .......

5 0

3 years ago

One ball of mass 0.600kg travelling 9.00m/s to the right collides head on elastically with a second ball of mass 0.300kg travell

Alina [70]

Let m₁ and v₁ denote the mass and initial velocity of the first ball, and m₂ and v₂ the same quantities for the second ball. Momentum is conserved throughout the collision, so

m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'

where v₁' and v₂' are the balls' respective velocities after the collision.

Kinetic energy is also conserved, so

1/2 m₁ v₁² + 1/2 m₂ v₂² = 1/2 m₁ (v₁')² + 1/2 m₂ (v₂')²

m₁ v₁² + m₂ v₂² = m₁ (v₁')² + m₂ (v₂')²

From the momentum equation, we have

(0.600 kg) (9.00 m/s) + (0.300 kg) (-8.00 m/s) = (0.600 kg) v₁' + (0.300 kg) v₂'

which simplifies to

10.0 m/s = 2 v₁' + v₂'

so that

v₂' = 10.0 m/s - 2 v₁'

From the energy equation, we have

(0.600 kg) (9.00 m/s)² + (0.300 kg) (-8.00 m/s)² = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²

which simplifies to

67.8 J = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²

226 m²/s² = 2 (v₁')² + (v₂')²

Substituting v₂' yields

226 m²/s² = 2 (v₁')² + (10.0 m/s - 2 v₁')²

which simplifies to

3 (v₁')² - (20.0 m/s) v₁' - 63.0 m²/s² = 0

Solving for v₁' using the quadratic formula gives two solutions,

v₁' ≈ -2.33 m/s or v₁' = 9.00 m/s

but the second solution corresponds to the initial conditions, so we omit that one.

Then the second ball has velocity

v₂' = 10.0 m/s - 2 (-2.33 m/s)

v₂' ≈ 14.7 m/s

6 0

2 years ago

Which of the following statements is most likely to be true of pseudoscience?

stiks02 [169]

C. spokesperson are respected members of the scientific community

8 0

4 years ago

Read 2 more answers

Help plss .. Two bicyclists are accelerating forward in a straight line, and Biker 1 has less

castortr0y [4]

Explanation:

Remember Newton's Second Law.

$F=ma$

If the force acting on both bikers is the same, we can look at the relationship between acceleration and mass.

If Biker 1 has a mass of 10kg and Biker 2 has a mass of 20kg, and both are being acted upon by a force of 100 N, let's see what that looks like. $100 = 10*a_1 \rightarrow a_1 = 100/10 = 10$

$100 = 20 *a_2 \rightarrow a_2 = 100/20 = 5$

So, given the same force, an object with GREATER mass will have less acceleration.

4 0

3 years ago