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4 years ago

What is it called when something doesn’t flow easy

Physics

1 answer:

LUCKY_DIMON [66]4 years ago

7 0

Answer:

That something is called having a high viscosity.

Explanation:

The measure expressing a "resistance to flow" is called viscosity. Viscosity relates to internal friction forces in a fluid causing it to flow with more or less difficulty. Highly viscous stuff is perceived "thick" or "sticky."

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A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northwest. After 25.0s, what is the magnitude

kondaur [170]

Answer:

81.8 m/s

Explanation:

The initial velocity of the plane is:

$v_0=115 m/s$ (toward east)

So, decomposing along the x- and y- directions:

$v_{x0} = 115 m/s\\v_{y0} = 0$

(we took east as positive x-direction and north as positive y-direction)

The acceleration is

$a=2.88 m/s^2$ (northwest, so the angle with the positive x-direction is 135 degrees)

Decomposing it along the two directions:

$a_x = a cos 135^{\circ} = (2.88 m/s^2)(cos 135^{\circ})=-2.04 m/s^2\\a_y = a sin 135^{\circ} = (2.88 m/s^2)(sin 135^{\circ})=2.04 m/s^2$

So the two components of the velocity after a time t = 25.0 s will be

$v_x = v_{x0} + a_x t = 115 m/s + (-2.04 m/s^2)(25.0 s)=64 m/s\\v_y = v_{y0} + a_y t = 0 m/s + (2.04 m/s^2)(25.0 s)=51 m/s$

So, the magnitude of the velocity of the plane will be

$v=\sqrt[v_x^2+v_y^2}=\sqrt{(64 m/s)^2+(51 m/s)^2}=81.8 m/s$

6 0

3 years ago

What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

kkurt [141]

Answer:

$4.3\cdot 10^{-12} J$

Explanation:

The fusion reaction in this problem is

$4^1_1H \rightarrow ^4_2He +2e^+$

The total energy released in the fusion reaction is given by

$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

The conversion factor between atomic mass units and kilograms is

$1u=1.66054\cdot 10^{-27}kg$

So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

$\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J$

6 0

3 years ago

You rubbed two identical balloons in your hair's friend. This causes the balloons to become charged negatively with a magnitude

dem82 [27]

Answer:

a) F = 2.25 10³ N, b) REPULSIVE.

Explanation:

a) The electric force is given by coulomb's law

F = $k \frac{q_1q_2}{r^2}$ k q1q2 / r2

in this case nso indicate that the two charges have the same value

q₁ = q₂ = 2.5 10⁻⁶ C

Let's reduce the magnitudes to the SI system

r = 0.5 cm (1m / 100cm) = 5 10⁻³ m

let's calculate

F = $9 \ 10^9 \frac{(2.5 \ 10^{-6})^2 }{(5 \ 10^{-3})^2}$

F = 2.25 10³ N

b) In electricity, electric charges of the same sign repel and those of the opposite sign attract

In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.

7 0

3 years ago

Two technicians are discussing a state emission test. Technician A says that a vent valve that is not able to close can cause th

Stolb23 [73]

Answer: correct option is C

both Technicians A and B are right

Explanation:

Test cycles specify the specific conditions under which the engine or vehicle is operated during the emission test. The vent valve that is not able to close can cause the system to fail the on-board test. Also, a leaking gas cap can cause a failure of the EVAP test.

There are many different test cycles issued by various national and international governments and working groups

3 0

3 years ago

very dense * powerful gravitational field * extremely compact space object * spectroscope data reveal swirling gas Observations

pickupchik [31]

All of the observations except "powerful gravitational field" are consistent with the current theory of black holes.

The gavitational field of a black hole is thought to be no different than that of an ordinary star with the same mass.

5 0

3 years ago