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pogonyaev
2 years ago
12

Which particle has an electronic structure of 2.8.8?

Chemistry
2 answers:
svetlana [45]2 years ago
7 0

Answer:

Argon

Explanation:

Argon has a electron configuration of 2.8.8. This shows an octate state, meaning that it has no lose pair of electrons. It has a total of 18 electrons on its shell

alina1380 [7]2 years ago
6 0

Answer:

argon has an element structure of 2.8.8

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What does a salt bridge do?
Andrew [12]

Answer:

A salt bridge or ion bridge, in electrochemistry, is a laboratory device used to connect the oxidation and reduction half-cells of a galvanic cell (voltaic cell), a type of electrochemical cell. It maintains electrical neutrality within the internal circuit.

Explanation:

5 0
3 years ago
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An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be 8-2-2+8+. If the
Mrrafil [7]

Answer: 1) p⁺ = 22; number of protons.

e⁻ = 19 - 1 = 18; number of electrons.

Net charge is +4, because atom has 4 protons more than electrons.

Proton is a subatomic particle with a positive electric charge of +1e elementary charge.

2) p⁺ = 22; number of protons.

e⁻ = 19 + 3 = 22; number of electrons.

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Hope this helps :)

4 0
3 years ago
Modern pennies are composed of zinc coated with copper. A student determines the mass of a penny to be 2.483 g and then makes se
Aleonysh [2.5K]

Answer:

97.1%

Explanation:

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The stoichiometry of the reaction is now used to obtain the number of moles of Zn that will produce a given number of moles of hydrogen from the balanced reaction equation as shown. This gives us the number of moles of zinc reacted hence the mass of zinc in the coin since it is assumed that all the zinc reacts.

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3 0
3 years ago
Which type of reaction has will give brainliest to first correct answer
k0ka [10]

Answer:

I think it's replacement because the B and D just swap places in the end equation

7 0
3 years ago
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If 12.8 g lead(II) sulfate (303.3 g/mol) precipitates when excess potassium chloride is added to 1.65 L of a water sample, what
quester [9]

Answer:

M=0.0256M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

PbSO_4(aq)+2KCl(aq)\rightarrow PbCl_2(s)+K_2SO_4(aq)

In such a way, since all the lead (II) is converted due to the excess of potassium chloride, the moles of lead (II) in the sample are computed from the mass of lead (II) sulfate:

n_{Pb^{2+}}=12.8gPbSO_4*\frac{1molPbSO_4}{303.3gPbSO_4} *\frac{1molPb^{2+}}{1molPbSO_4} \\\\n_{Pb^{2+}}=0.0422molPb^{2+}

Thus, since volume of the solution is 1.65 due to the fact that the addition of the reactants is not enough to significantly modify the reaction's volume, the resulting molar concentration of the lead (II) ions is:

M=\frac{n_{Pb^{2+}}}{V}=\frac{0.0422molPb^{2+}}{1.65L}\\  \\M=0.0256M

Regards.

5 0
3 years ago
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